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Question

Consider the molecules / ions given below
$XeO_3$, $BF_4^-$, $I_3^-$, $SF_6$, $PCl_5$
The ratio of number of molecules having $sp^3d$ hybridisation to those having $sp^3$ hybridisation is ________

Hybridization Analysis of Given Species

We need to determine the hybridization of each molecule/ion: $XeO_3$, $BF_4^-$, $I_3^-$, $SF_6$, and $PCl_5$. This involves calculating the steric number (number of atoms bonded to the central atom + number of lone pairs on the central atom).

1. Determining Hybridization

  • $XeO_3$: Central atom Xe. Steric Number = 3 (Xe-O bonds) + 1 (lone pair) = 4. Hybridization = $sp^3$.
  • $BF_4^-$: Central atom B. Steric Number = 4 (B-F bonds) + 0 (lone pairs) = 4. Hybridization = $sp^3$.
  • $I_3^-$: Central atom I. Steric Number = 2 (I-I bonds) + 3 (lone pairs) = 5. Hybridization = $sp^3d$.
  • $SF_6$: Central atom S. Steric Number = 6 (S-F bonds) + 0 (lone pairs) = 6. Hybridization = $sp^3d^2$.
  • $PCl_5$: Central atom P. Steric Number = 5 (P-Cl bonds) + 0 (lone pairs) = 5. Hybridization = $sp^3d$.

Hybridization Summary Table

Molecule/Ion Steric Number Hybridization
$XeO_3$ 4 $sp^3$
$BF_4^-$ 4 $sp^3$
$I_3^-$ 5 $sp^3d$
$SF_6$ 6 $sp^3d^2$
$PCl_5$ 5 $sp^3d$

Calculating the Ratio

From the analysis above:

  • Number of species with $sp^3d$ hybridization = 2 ($I_3^-$ and $PCl_5$).
  • Number of species with $sp^3$ hybridization = 2 ($XeO_3$ and $BF_4^-$).

The required ratio is calculated as:

Ratio = (Number of $sp^3d$ species) / (Number of $sp^3$ species)

Using LaTeX notation:

Ratio = = 1

The ratio of the number of molecules having $sp^3d$ hybridization to those having $sp^3$ hybridization is 1.

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  5. Which of the following is the structure of pyrosulphuric acid?
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