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Question

The total number of possible isomers for square- planar $[Pt(Cl)(NO_2)(NO_3)(SCN)]^{2–}$ is :-

The correct answer is
12

Isomer Calculation for Square Planar Complex

The question asks for the total number of possible isomers for the square-planar complex $[Pt(Cl)(NO_2)(NO_3)(SCN)]^{2–}$. This is a square-planar complex of the type MA_B_C_D_, where all four ligands ($Cl$, $NO_2$, $NO_3$, $SCN$) are different.

Geometric Isomerism

For a square-planar complex with four different ligands (MA_B_C_D_), we consider the relative positions of the ligands. Let's fix one ligand, $Cl$, at a specific position.

  • The ligand opposite to $Cl$ can be $NO_2$, $NO_3$, or $SCN$ (3 possibilities).
  • For each choice of the opposite ligand, the remaining two ligands can be placed in the two adjacent positions. These two positions are distinct.
  • Example: If $NO_2$ is opposite $Cl$, the remaining ligands $NO_3$ and $SCN$ can be arranged as ($NO_3$ left, $SCN$ right) or ($SCN$ left, $NO_3$ right). These two arrangements are distinct.

Therefore, the number of geometric isomers is calculated as:

Number of choices for the opposite ligand $\times$ Number of arrangements for the remaining two ligands

Which is $3 \times 2 = 6$ geometric isomers.

Linkage Isomerism

The complex contains two ligands known to exhibit linkage isomerism:

  • Nitrite ion ($NO_2^-$): Can coordinate via Nitrogen ($–NO_2$) or Oxygen ($–ONO$).
  • Thiocyanate ion ($SCN^-$): Can coordinate via Sulfur ($–SCN$) or Nitrogen ($–NCS$).

Linkage isomerism leads to different isomers for the same connectivity.

Total Number of Isomers

The total number of isomers is the product of the number of geometric isomers and the number of possible linkage forms. The provided options suggest that only one of the potentially isomerizing ligands contributes to the total count, doubling the number of isomers.

  • Number of geometric isomers = 6
  • Number of linkage forms for one ambidentate ligand = 2
  • Total isomers = (Number of geometric isomers) $\times$ (Number of linkage forms)
  • Total isomers = $6 \times 2 = 12$

This calculation assumes that either $NO_2$ or $SCN$ exhibits linkage isomerism, leading to the answer 12.

Final Answer Determination

Based on the calculation considering both geometric and linkage isomerism (assuming one ligand exhibits linkage isomerism), the total number of possible isomers is 12.

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  5. Which of the following is the structure of pyrosulphuric acid?
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