Manish is facing South. He took 90° right and walked 8 km. then he turn right and walked 6 km. What is the minimum distance between starting point to ending point?
10 km
This question asks us to find the minimum distance between Manish's starting point and his ending point after a series of movements based on directions and turns.
Let's break down Manish's path step by step:
The minimum distance between the starting point and the ending point is the straight-line distance, which is the displacement.
The path taken by Manish (8 km West followed by 6 km North) forms two sides of a right-angled triangle. The 8 km movement is along the West-East axis, and the 6 km movement is along the North-South axis. These two paths are perpendicular to each other, forming the two shorter sides (legs) of a right-angled triangle. The minimum distance between the start and end points is the hypotenuse of this triangle.
We can use the Pythagorean theorem to find the length of the hypotenuse (\(c\)), given the lengths of the two legs (\(a\) and \(b\)). The theorem states:
\[c^2 = a^2 + b^2\]
In this case:
Substituting the values into the theorem:
\[c^2 = (8 \, \text{km})^2 + (6 \, \text{km})^2\]
\[c^2 = 64 \, \text{km}^2 + 36 \, \text{km}^2\]
\[c^2 = 100 \, \text{km}^2\]
To find \(c\), we take the square root of both sides:
\[c = \sqrt{100 \, \text{km}^2}\]
\[c = 10 \, \text{km}\]
So, the minimum distance between Manish's starting point and ending point is 10 km.
| Action | Direction/Turn | Distance | New Position (relative to Start) |
|---|---|---|---|
| Starting | Facing South | 0 km | (0,0) |
| 1st Movement | 90° Right (towards West) | 8 km | (-8, 0) |
| 2nd Movement | Right Turn (towards North) | 6 km | (-8, 6) |
The straight line from (0,0) to (-8,6) is the minimum distance, which is 10 km.
| Concept | Explanation | How it Applied Here |
|---|---|---|
| Cardinal Directions | North, South, East, West. Used as primary reference points. | Movements were West and North. |
| Turns (Right/Left) | Right turn is 90° clockwise. Left turn is 90° counter-clockwise. | Manish took 90° right turns from South (to West) and from West (to North). |
| Minimum Distance (Displacement) | The shortest straight-line distance between the initial and final positions. | Calculated as the hypotenuse of the right-angled triangle formed by the movements. |
| Pythagorean Theorem | In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides (\(a^2 + b^2 = c^2\)). | Used to find the minimum distance (hypotenuse) from the two perpendicular movements (legs). |
Problems involving direction and distance often require visualizing movements and using basic geometry, particularly the Pythagorean theorem, to find the shortest path or displacement.
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