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Question

List – IList – II  
a. Multiplexeri. Selects one of many inputs to a single output
b. Flip-Flopii. Combinational circuit
c. Shift Registeriii. Memory
d. Parallel Adderiv. Sequential logic

Codes :

This question was previously asked in
UGC NET 2014 Paper 1 Question Paper (28-Dec-2014)
The correct answer is

a-i, b-iii, c-iv, d-ii

 Every option pairs the multiplexer with (i), so the question really turns on the other three.

(a) Multiplexer → (i) selects one of many inputs to a single output. That is the definition — a data selector. With n select lines it routes one of \(2^{n}\) inputs through, according to

\(Y=\sum_{i=0}^{2^{n}-1}m_{i}I_{i}\)

(b) Flip-flop → (iii) memory. A flip-flop is the elementary one-bit store: it holds its state indefinitely until clocked, which is precisely what memory means. Every register, counter and RAM cell is built from them.

(c) Shift register → (iv) sequential logic. Its output depends not only on the present input but on what was clocked in previously — the defining property of a sequential circuit. It is made of flip-flops in a chain, each feeding the next.

(d) Parallel adder → (ii) combinational circuit. The sum depends only on the bits presently applied; there is no clock and no stored state. Give it the same inputs and it always gives the same output.

The order (i), (iii), (iv), (ii) is option 1.

 CombinationalSequential
Output depends onPresent inputs onlyPresent inputs and past history
Memory elementNoneFlip-flops
ClockNot requiredUsually required
ExamplesAdder, MUX, decoder, encoder, comparatorFlip-flop, register, counter, state machine

The distinction is the organising principle of the whole subject, and the multiplexer illustrates it neatly: although it is combinational, a MUX with its output fed back to one input becomes a storage element — which is exactly how a D flip-flop with an enable is built. The line between the two families is feedback.

A note on the parallel adder : the ripple-carry version is combinational but slow, since the carry must propagate through all n stages, giving a delay proportional to n. The carry-look-ahead adder computes every carry directly from the inputs, reducing the delay to a constant at the cost of more gates — still entirely combinational.

Hence, the correct match is a-i, b-iii, c-iv, d-ii.

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Similar Questions

  1. Assertion (A) : A demultiplexer can be used as a decoder.

    Reason (R) : A demultiplexer is built by using AND gates only.

  2. Match the following :

    List – I List – II 
    a. Shift Registeri. Frequency Division
    b. Multiplexerii. Memory chip select generation
    c. Decoderiii. Parallel to serial conversion
    d. Counteriv. Many to one switch

    Codes :

  3. Match the following :

     List - I List - II
    (a) Minimization(i) Multiplexer
    (b) Successive Approximation(ii) Shift Register
    (c) Data Selector(iii) A/D Convertor
    (d) Sequence Generator(iv) QM Metdod

    Codes :

  4. Assertion (A) : A decoder is dissimilar to a demultiplexer.

    Reason (R) : There is no data input in a decoder.

    Select your answer using the codes given below.


Important Questions from Combinational Circuits

  1. Which of the following represents the borrow in a half subtraction?

  2. Carry input is present in which of the following?

  3. The number of control lines for 8-to-1 multiplexer is:

  4. X/Y (where X represents the input code and Y represents the output code) as a qualifying symbol does NOT relate to:

  5. Consider 4-bit gray code representation of numbers. Let h3 h2 h1 h0 be the gray code representation of a number n and g1g2g3g0 be the gray code representation of the number (n + 1) modulo 16. Which one of the following functions is correct?

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