Lines AB and CD are parallel, with A and C to the left of the transversal XY, and B and D to the right. The transversal intersects AB at M and CD at N, where X, M, N, and Y are collinear in that order. If measure of ∠XMA=125°, then the measure of ∠CNY is:
55°
Since AB ∥ CD and XY is a transversal cutting AB at M and CD at N, the angle ∠XMA at M and the angle ∠MNC at N are corresponding angles (both are on the left side of the transversal, above their respective lines from N's viewpoint).
By the corresponding angles postulate, \(\angle MNC = \angle XMA = 125°\).
At point N, the angles ∠MNC and ∠CNY form a linear pair along the straight line XY, so \(\angle MNC + \angle CNY = 180°\).
Therefore, \(\angle CNY = 180° - 125° = 55°\).
Hence, the measure of ∠CNY is 55°.
What is the sum of the angle complementary to $15^\circ$ and the angle supplementary to $125^\circ$?
There are three points P, Q and R on a straight line such that PQ : QR = 3 : 5. If n is the number of possible values of PQ : PR, then what is n equal to ?
Two cars start from a point at the same time and travel on two different roads at right angles to each other. Their speed is 18 km/h and 72 km/h respectively. What will be the distance between them after 6 seconds?
Express 65° in radian :
The measure of an angle for which the measure of the supplement is four times the measure of the complement is:
AB||CD and EF is the transversal meeting AB and CD at P and Q, respectively. If ∠APE = 6x and ∠PQD = 4x, then ∠APQ =______.