Let the measure of the unknown angle be $x$.
Two angles are supplementary if their sum is $180^{\circ}$. Therefore, the supplementary angle to $x$ measures $180^{\circ} - x$.
The problem states that the measure of the angle ($x$) is one half of its supplementary angle ($180^{\circ} - x$). This can be written as an equation:
$x = \frac{1}{2} (180^{\circ} - x)$
To find the measure of the angle, we solve the equation:
$2 \times x = 2 \times \frac{1}{2} (180^{\circ} - x)$
$2x = 180^{\circ} - x$
$2x + x = 180^{\circ} - x + x$
$3x = 180^{\circ}$
$x = \frac{180^{\circ}}{3}$
$x = 60^{\circ}$
Thus, the measure of the angle is $60^{\circ}$.
What is the sum of the angle complementary to $15^\circ$ and the angle supplementary to $125^\circ$?
In the given figure, AB and CD are parallel lines. O is a point such that angle CDO = $70^\circ$ and angle DOB = $100^\circ$. Find angle ABO.
If angles of a triangle are in the ration of 2 : 3 : 4, then the measure of the smallest angle is:
In the triangle, if AB = AC and ∠ABC = 72°, then ∠BAC is:
The angles of a triangle are (8x - 15)°,(6x - 11)° and ( 4x – 10)°. What is the value of x ?
In a ΔABC, the bisectors of ∠B and ∠C meet at point O, inside the triangle. If ∠BOC = 122°, then the measure of ∠A is:
In ΔABC, D is a point on side BC such that ∠ADC = 2∠BAD. If ∠A = 80° and ∠C = 38°, then what is the measure of ∠ADB?