Let X and Y represent prices (in Rs) of a commodity in Kolkata and Mumbai respectively. It is given X̅ = 65, Y̅ = 67, σ X = 2.5, σ Y = 3.5 and r(X, Y) = 0.8. What is the equation of regression of Y on X ?
Y = 1.12X - 5.8
The question asks for the equation of the regression of Y on X, where X and Y represent prices of a commodity in Kolkata and Mumbai, respectively. This equation helps us predict the price in Mumbai (Y) based on the price in Kolkata (X).
We are given the following information:
The equation of the regression line of Y on X is given by \(Y = a + b_{YX}X\), where \(b_{YX}\) is the regression coefficient of Y on X and \(a\) is the y-intercept.
The formula for the regression coefficient \(b_{YX}\) is:
\(b_{YX} = r \frac{\sigma_Y}{\sigma_X}\)
Let's substitute the given values into the formula:
\(b_{YX} = 0.8 \times \frac{3.5}{2.5}\)
Calculating the value:
\(b_{YX} = 0.8 \times 1.4\)
\(b_{YX} = 1.12\)
So, the regression coefficient of Y on X is \(1.12\). This means that for every one-unit increase in the price in Kolkata (X), the price in Mumbai (Y) is expected to increase by \(1.12\) units, on average.
The regression line of Y on X always passes through the mean point \((\bar{X}, \bar{Y})\). We can use this property to find the y-intercept \(a\). The equation \(\bar{Y} = a + b_{YX}\bar{X}\) holds true.
We can rearrange this formula to solve for \(a\):
\(a = \bar{Y} - b_{YX}\bar{X}\)
Now, let's substitute the values of \(\bar{Y}\), \(b_{YX}\), and \(\bar{X}\):
\(a = 67 - (1.12 \times 65)\)
First, calculate the product \(1.12 \times 65\):
\(1.12 \times 65 = 72.8\)
Now, calculate \(a\):
\(a = 67 - 72.8\)
\(a = -5.8\)
The y-intercept is \(-5.8\). This is the predicted price in Mumbai when the price in Kolkata is 0 (though this interpretation may not be meaningful in the context of prices).
Now that we have the regression coefficient \(b_{YX} = 1.12\) and the y-intercept \(a = -5.8\), we can write the equation of the regression of Y on X:
\(Y = a + b_{YX}X\)
Substituting the calculated values:
\(Y = -5.8 + 1.12X\)
Rearranging the terms to match the standard form:
\(Y = 1.12X - 5.8\)
This is the equation that predicts the price in Mumbai (Y) based on the price in Kolkata (X).
Let's compare our derived equation, \(Y = 1.12X - 5.8\), with the given options:
Our calculated equation matches Option 2.
| Concept | Description | Formula (Y on X) |
|---|---|---|
| Regression Line of Y on X | Equation used to predict Y based on X. | \(Y = a + b_{YX}X\) |
| Regression Coefficient (\(b_{YX}\)) | Measures the change in Y for a one-unit change in X. | \(b_{YX} = r \frac{\sigma_Y}{\sigma_X}\) |
| Y-intercept (\(a\)) | The value of Y when X is 0; calculated using means. | \(a = \bar{Y} - b_{YX}\bar{X}\) |
| Correlation Coefficient (\(r\)) | Measures the strength and direction of the linear relationship between X and Y. | \(r(X, Y)\) (given) |
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