A bivariate data set contains only two points (-1, 1) and (3, 2). What will be the line of regression of y on x ?
x - 4y + 5 = 0
A bivariate data set involves observations on two variables for each individual or data point. In this question, we are given a very simple bivariate data set consisting of just two points: (-1, 1) and (3, 2).
The line of regression of y on x is essentially a line that describes how the variable y is expected to change as the variable x changes. When you only have two data points, the line of regression of y on x is simply the straight line that passes through these two points. There is no complex fitting required as the line through two distinct points is unique.
To find the equation of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\), we first need to calculate the slope (m) of the line using the formula:
\( m = \frac{y_2 - y_1}{x_2 - x_1} \)
Once we have the slope, we can use the point-slope form of the linear equation, which is:
\( y - y_1 = m(x - x_1) \)
Alternatively, we can find the y-intercept (c) using the slope-intercept form \(y = mx + c\) by substituting one of the points into the equation.
Our two points are \((-1, 1)\) and \((3, 2)\).
| Point | x-coordinate | y-coordinate |
|---|---|---|
| 1 | -1 | 1 |
| 2 | 3 | 2 |
Let \((x_1, y_1) = (-1, 1)\) and \((x_2, y_2) = (3, 2)\).
Now, we calculate the slope:
\( m = \frac{2 - 1}{3 - (-1)} \)
\( m = \frac{1}{3 + 1} \)
\( m = \frac{1}{4} \)
So, the slope of the line of regression is \(\frac{1}{4}\).
We have the slope \(m = \frac{1}{4}\) and we can use either of the two points. Let's use the point \((-1, 1)\) and the point-slope form \(y - y_1 = m(x - x_1)\).
Substitute the values:
\( y - 1 = \frac{1}{4}(x - (-1)) \)
\( y - 1 = \frac{1}{4}(x + 1) \)
To remove the fraction, multiply both sides of the equation by 4:
\( 4(y - 1) = 4 \times \frac{1}{4}(x + 1) \)
\( 4y - 4 = x + 1 \)
Now, rearrange the terms to get the equation in the standard form \(Ax + By + C = 0\):
\( 0 = x - 4y + 1 + 4 \)
\( 0 = x - 4y + 5 \)
Or, writing it conventionally:
\( x - 4y + 5 = 0 \)
This is the equation of the line of regression of y on x for the given bivariate data set.
Let's compare our derived equation \(x - 4y + 5 = 0\) with the given options:
Our equation matches option 1.
| Concept | Description | Formula (if applicable) |
|---|---|---|
| Bivariate Data | Data involving two variables for each observation. | N/A |
| Line of Regression of y on x | A line describing the relationship between x and y, used to predict y based on x. With two points, it's the line connecting them. | General form: \(y = a + bx\) |
| Slope of a Line | Measure of the steepness of a line, indicating the rate of change of y with respect to x. | \( m = \frac{y_2 - y_1}{x_2 - x_1} \) |
| Point-Slope Form | Equation of a line given a point \((x_1, y_1)\) and slope m. | \( y - y_1 = m(x - x_1) \) |
While for two points the regression line is simply the line connecting them, for more than two points, the line of regression (either y on x or x on y) is calculated using methods like the method of least squares. This method minimizes the sum of the squared errors (the vertical distances from the points to the line for y on x regression). The formulas for the slope (b) and y-intercept (a) of the regression line \(y = a + bx\) for n points are:
Where \(\bar{x}\) and \(\bar{y}\) are the means of x and y respectively, and n is the number of data points. For two points, these complex formulas simplify to the line through the points.
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