Variable Y regresses with variable X with the conditions that \(\overline X = 5.50\) , \(\overline Y = 3.50\) and b = 1.50 in the linear regression model (Y = a + bX), where \(\overline Y\) and \(\overline X\) are means of the respective variables and b refers to gradient of line of Y w. r. t X. Which one of the following values of parameter 'a' of the model is correct?
-4.75
The question asks us to find the value of the parameter 'a' in a linear regression model. A linear regression model describes the relationship between two variables, typically denoted as Y (dependent variable) and X (independent variable), using a straight line equation.
The standard form of a simple linear regression model is given by:
\(Y = a + bX\)
Where:
A fundamental property of the least squares regression line is that it always passes through the point defined by the means of the variables, i.e., \((\overline X, \overline Y)\). This means that if we substitute the mean values of X and Y into the regression equation, the equation should hold true:
\(\overline Y = a + b\overline X\)
This property is very useful because it allows us to find one of the parameters (a or b) if the other parameter and the means are known.
We are provided with the following information:
We need to find the value of the parameter 'a'.
Using the property that the regression line passes through the means, we substitute the given values into the equation \(\overline Y = a + b\overline X\):
\(3.50 = a + (1.50 \times 5.50)\)
First, calculate the product of 'b' and \(\overline X\):
\(1.50 \times 5.50\)
We can calculate this as:
\(1.5 \times 5.5 = 1.5 \times (5 + 0.5) = (1.5 \times 5) + (1.5 \times 0.5)\)
\(1.5 \times 5 = 7.5\)
\(1.5 \times 0.5 = 0.75\)
So, \(1.50 \times 5.50 = 7.5 + 0.75 = 8.25\)
Now, substitute this value back into the equation:
\(3.50 = a + 8.25\)
To find 'a', we need to isolate it on one side of the equation. Subtract 8.25 from both sides:
\(a = 3.50 - 8.25\)
Calculating the difference:
\(3.50 - 8.25 = - (8.25 - 3.50)\)
\(8.25 - 3.50 = 4.75\)
Therefore,
\(a = -4.75\)
With the calculated value of 'a' and the given value of 'b', the linear regression model is:
\(Y = -4.75 + 1.50X\)
Based on the calculations using the given means and slope, the value of the parameter 'a' is -4.75.
| Parameter | Symbol | Description | How it's found (simple regression) |
|---|---|---|---|
| Intercept | a | Value of Y when X=0 (Y-intercept) | \(\overline Y - b\overline X\) |
| Slope / Gradient | b | Change in Y for a unit change in X | \(\frac{\sum(X_i - \overline X)(Y_i - \overline Y)}{\sum(X_i - \overline X)^2}\) or \(\frac{Cov(X, Y)}{Var(X)}\) |
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