If two lines of regression are x + 4y + 1 = 0 and 4x + 9y + 7 = 0, then what is the value of x when y = -3 ?
5
The question asks us to find the value of \(x\) for a given value of \(y = -3\), using two linear equations representing regression lines: \(x + 4y + 1 = 0\) and \(4x + 9y + 7 = 0\).
In regression analysis, we typically have two regression lines: the regression line of \(x\) on \(y\) and the regression line of \(y\) on \(x\). The regression line of \(x\) on \(y\) is used to estimate \(x\) for a given value of \(y\), and the regression line of \(y\) on \(x\) is used to estimate \(y\) for a given value of \(x\).
To answer this question, we need to identify which of the two given equations is the regression line of \(x\) on \(y\). We can determine this by considering the properties of regression coefficients. Let \(b_{xy}\) be the regression coefficient of \(x\) on \(y\) and \(b_{yx}\) be the regression coefficient of \(y\) on \(x\). A key property is that the product of the regression coefficients must lie between 0 and 1, i.e., \(0 \le b_{xy} \cdot b_{yx} \le 1\). Also, \(b_{xy}\) and \(b_{yx}\) must have the same sign.
Let's analyze the two given equations:
Equation 1: \(x + 4y + 1 = 0\)
Equation 2: \(4x + 9y + 7 = 0\)
We can express each equation in terms of \(x\) as a function of \(y\) (to find \(b_{xy}\)) and \(y\) as a function of \(x\) (to find \(b_{yx}\)).
From Equation 1:
From Equation 2:
Now let's consider the two possible cases for assigning the regression lines and check the condition \(0 \le b_{xy} \cdot b_{yx} \le 1\).
Case 1: Assume Equation 1 is \(x\) on \(y\) and Equation 2 is \(y\) on \(x\).
The product \(b_{xy} \cdot b_{yx} = (-4) \cdot (-\frac{4}{9}) = \frac{16}{9}\). Since \(\frac{16}{9} > 1\), this case is not possible according to the property of regression coefficients.
Case 2: Assume Equation 1 is \(y\) on \(x\) and Equation 2 is \(x\) on \(y\).
The product \(b_{xy} \cdot b_{yx} = (-\frac{9}{4}) \cdot (-\frac{1}{4}) = \frac{9}{16}\). Since \(0 \le \frac{9}{16} \le 1\), this case is valid.
Therefore, the regression line of \(x\) on \(y\) is Equation 2: \(4x + 9y + 7 = 0\).
The question asks for the value of \(x\) when \(y = -3\). We substitute \(y = -3\) into the equation of the regression line of \(x\) on \(y\).
\[ 4x + 9y + 7 = 0 \]Substitute \(y = -3\):
\[ 4x + 9(-3) + 7 = 0 \] \[ 4x - 27 + 7 = 0 \] \[ 4x - 20 = 0 \] \[ 4x = 20 \] \[ x = \frac{20}{4} \] \[ x = 5 \]So, the value of \(x\) when \(y = -3\) is 5.
Regression lines are used in statistics to model the relationship between two variables. One line predicts \(y\) from \(x\), and the other predicts \(x\) from \(y\).
The two regression lines intersect at the point \((\bar{x}, \bar{y})\), which are the means of \(x\) and \(y\) respectively.
For two variables \(x\) and \(y\):
Following these steps, we correctly identified \(4x + 9y + 7 = 0\) as the regression line of \(x\) on \(y\) and calculated \(x=5\) when \(y=-3\).
| Equation | Possible \(b_{xy}\) (solving for x) | Possible \(b_{yx}\) (solving for y) |
|---|---|---|
| \(x + 4y + 1 = 0\) | -4 | -1/4 |
| \(4x + 9y + 7 = 0\) | -9/4 | -4/9 |
Checking products:
Thus, \(4x + 9y + 7 = 0\) is the regression line of \(x\) on \(y\).
Substitute \(y = -3\):
\[ 4x + 9(-3) + 7 = 0 \] \[ 4x - 27 + 7 = 0 \] \[ 4x - 20 = 0 \] \[ 4x = 20 \] \[ x = 5 \]The regression line \(x = -\frac{9}{4}y - \frac{7}{4}\) tells us that for every one-unit increase in \(y\), \(x\) is estimated to decrease by \(9/4\) units. When \(y = -3\), we can estimate \(x\) using this relationship, which we found to be 5.
| Concept | Description | Key Property |
|---|---|---|
| Regression Line \(y\) on \(x\) | Predicts \(y\) based on \(x\) values. Form: \(y = a + b_{yx}x\). | Slope is \(b_{yx}\). |
| Regression Line \(x\) on \(y\) | Predicts \(x\) based on \(y\) values. Form: \(x = c + b_{xy}y\). | Slope is \(b_{xy}\). |
| Intersection Point | The point \((\bar{x}, \bar{y})\). Both lines pass through this point. | Represents the mean of \(x\) and \(y\). |
| Product of Coefficients | \(b_{xy} \cdot b_{yx}\) | Must be between 0 and 1 (\(0 \le b_{xy} \cdot b_{yx} \le 1\)). Equal to \(r^2\). |
| Sign of Coefficients | \(b_{xy}\) and \(b_{yx}\) | Always have the same sign. |
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