Direction: Consider the following for the next two (02) items that follow. Two regression lines are given as 3x - 4y + 8 = 0 and 4x - 3y - 1 = 0.
Consider the following statements: 1. The coefficient of correlations r is \(\rm \frac{3}{4}\) . 2. The means of x and y are 3 and 4 respectively. Which of the above statements is/are correct?
1 only
The problem provides two regression lines and asks us to evaluate two statements regarding the coefficient of correlation and the means of x and y.
Regression lines are used in statistics to model the relationship between two variables. The intersection point of the two regression lines (regression line of y on x and regression line of x on y) represents the means of the two variables, \(\bar{x}\) and \(\bar{y}\). The slope of these lines is related to the regression coefficients, which in turn are related to the coefficient of correlation (r).
The means of x and y are the coordinates of the point where the two regression lines intersect. We can find this point by solving the given system of linear equations:
We can solve this system using the elimination method. Multiply Equation 1 by 4 and Equation 2 by 3 to make the coefficients of x equal:
Now, subtract Equation 4 from Equation 3:
\[ (12x - 16y) - (12x - 9y) = -32 - 3 \]
\[ 12x - 16y - 12x + 9y = -35 \]
\[ -7y = -35 \]
\[ y = \frac{-35}{-7} = 5 \]
Substitute the value of y = 5 into Equation 2:
\[ 4x - 3(5) = 1 \]
\[ 4x - 15 = 1 \]
\[ 4x = 1 + 15 \]
\[ 4x = 16 \]
\[ x = \frac{16}{4} = 4 \]
Thus, the means are \(\bar{x} = 4\) and \(\bar{y} = 5\). Statement 2 says the means of x and y are 3 and 4 respectively. This is incorrect.
The slopes of the regression lines are the regression coefficients. Let's assume one equation is the regression of y on x and the other is the regression of x on y.
From Equation 1 (\(3x - 4y + 8 = 0\)), express y in terms of x:
\[ 4y = 3x + 8 \implies y = \frac{3}{4}x + 2 \]
The slope of this line (assuming it's y on x) is the regression coefficient of y on x, denoted as \(b_{yx}\). So, \(b_{yx} = \frac{3}{4}\).
From Equation 2 (\(4x - 3y - 1 = 0\)), express x in terms of y:
\[ 4x = 3y + 1 \implies x = \frac{3}{4}y + \frac{1}{4} \]
The slope of this line (assuming it's x on y) is the regression coefficient of x on y, denoted as \(b_{xy}\). So, \(b_{xy} = \frac{3}{4}\).
The coefficient of correlation, r, is the geometric mean of the two regression coefficients: \(r^2 = b_{yx} \times b_{xy}\). The sign of r is the same as the sign of the regression coefficients.
\[ r^2 = \frac{3}{4} \times \frac{3}{4} = \frac{9}{16} \]
\[ r = \pm\sqrt{\frac{9}{16}} = \pm\frac{3}{4} \]
Since both \(b_{yx} = \frac{3}{4}\) and \(b_{xy} = \frac{3}{4}\) are positive, the correlation coefficient r must also be positive.
\[ r = +\frac{3}{4} \]
We can check if this assignment of regression lines was correct. For valid regression coefficients, their product \(b_{yx} \times b_{xy}\) must be less than or equal to 1 (which implies \(r^2 \le 1\)). In our case, \(r^2 = \frac{9}{16} \le 1\), so the assignment is consistent.
Statement 1 says the coefficient of correlation r is \(\frac{3}{4}\). This is correct.
Based on our calculations:
Therefore, only statement 1 is correct.
| Statement | Details | Correct/Incorrect |
|---|---|---|
| 1. Coefficient of correlation \(r = \frac{3}{4}\) | Calculated \(r = \frac{3}{4}\) from \(b_{yx} = \frac{3}{4}\) and \(b_{xy} = \frac{3}{4}\). | Correct |
| 2. Means \(\bar{x}=3\), \(\bar{y}=4\) | Calculated means by solving simultaneous equations: \(\bar{x}=4\), \(\bar{y}=5\). | Incorrect |
Statement 1 is correct, and Statement 2 is incorrect.
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In light of the above statements, choose the most appropriate answer from the options given below
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(c) The probable error of the Coefficient Correlation is 0.6745 times its standard error.
(d) Coefficient of Correlation multiplied by the ratio between the standard deviations of the two variables denotes the slope of the regression line.
Code:
If two regression coefficients are 0.8 and 1.2, which one of the following is the value of coefficient of correlation?