Direction: Consider the following for the next two (02) items that follow. Two regression lines are given as 3x - 4y + 8 = 0 and 4x - 3y - 1 = 0.
Consider the following statements: 1. The coefficient of correlations r is \(\rm \frac{3}{4}\) . 2. The means of x and y are 3 and 4 respectively. Which of the above statements is/are correct?
1 only
The problem provides two regression lines and asks us to evaluate two statements regarding the coefficient of correlation and the means of x and y.
Regression lines are used in statistics to model the relationship between two variables. The intersection point of the two regression lines (regression line of y on x and regression line of x on y) represents the means of the two variables, \(\bar{x}\) and \(\bar{y}\). The slope of these lines is related to the regression coefficients, which in turn are related to the coefficient of correlation (r).
The means of x and y are the coordinates of the point where the two regression lines intersect. We can find this point by solving the given system of linear equations:
We can solve this system using the elimination method. Multiply Equation 1 by 4 and Equation 2 by 3 to make the coefficients of x equal:
Now, subtract Equation 4 from Equation 3:
\[ (12x - 16y) - (12x - 9y) = -32 - 3 \]
\[ 12x - 16y - 12x + 9y = -35 \]
\[ -7y = -35 \]
\[ y = \frac{-35}{-7} = 5 \]
Substitute the value of y = 5 into Equation 2:
\[ 4x - 3(5) = 1 \]
\[ 4x - 15 = 1 \]
\[ 4x = 1 + 15 \]
\[ 4x = 16 \]
\[ x = \frac{16}{4} = 4 \]
Thus, the means are \(\bar{x} = 4\) and \(\bar{y} = 5\). Statement 2 says the means of x and y are 3 and 4 respectively. This is incorrect.
The slopes of the regression lines are the regression coefficients. Let's assume one equation is the regression of y on x and the other is the regression of x on y.
From Equation 1 (\(3x - 4y + 8 = 0\)), express y in terms of x:
\[ 4y = 3x + 8 \implies y = \frac{3}{4}x + 2 \]
The slope of this line (assuming it's y on x) is the regression coefficient of y on x, denoted as \(b_{yx}\). So, \(b_{yx} = \frac{3}{4}\).
From Equation 2 (\(4x - 3y - 1 = 0\)), express x in terms of y:
\[ 4x = 3y + 1 \implies x = \frac{3}{4}y + \frac{1}{4} \]
The slope of this line (assuming it's x on y) is the regression coefficient of x on y, denoted as \(b_{xy}\). So, \(b_{xy} = \frac{3}{4}\).
The coefficient of correlation, r, is the geometric mean of the two regression coefficients: \(r^2 = b_{yx} \times b_{xy}\). The sign of r is the same as the sign of the regression coefficients.
\[ r^2 = \frac{3}{4} \times \frac{3}{4} = \frac{9}{16} \]
\[ r = \pm\sqrt{\frac{9}{16}} = \pm\frac{3}{4} \]
Since both \(b_{yx} = \frac{3}{4}\) and \(b_{xy} = \frac{3}{4}\) are positive, the correlation coefficient r must also be positive.
\[ r = +\frac{3}{4} \]
We can check if this assignment of regression lines was correct. For valid regression coefficients, their product \(b_{yx} \times b_{xy}\) must be less than or equal to 1 (which implies \(r^2 \le 1\)). In our case, \(r^2 = \frac{9}{16} \le 1\), so the assignment is consistent.
Statement 1 says the coefficient of correlation r is \(\frac{3}{4}\). This is correct.
Based on our calculations:
Therefore, only statement 1 is correct.
| Statement | Details | Correct/Incorrect |
|---|---|---|
| 1. Coefficient of correlation \(r = \frac{3}{4}\) | Calculated \(r = \frac{3}{4}\) from \(b_{yx} = \frac{3}{4}\) and \(b_{xy} = \frac{3}{4}\). | Correct |
| 2. Means \(\bar{x}=3\), \(\bar{y}=4\) | Calculated means by solving simultaneous equations: \(\bar{x}=4\), \(\bar{y}=5\). | Incorrect |
Statement 1 is correct, and Statement 2 is incorrect.
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∑x = 130, ∑y = 220, ∑ x 2= 2288, ∑y 2= 5506 and ∑ xy = 3467.
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