The correlation coefficient (\(r\)) between two variables \(x\) and \(y\) can be determined from the slopes of the two regression lines. If the regression line of \(y\) on \(x\) is \(y = b_{yx}x + c_1\) and the regression line of \(x\) on \(y\) is \(x = b_{xy}y + c_2\), then the square of the correlation coefficient is given by \(r^2 = b_{yx} \cdot b_{xy}\). The sign of \(r\) is the same as the sign of the slopes \(b_{yx}\) and \(b_{xy}\).
We are given two lines:
We need to determine which line corresponds to the regression of \(y\) on \(x\) (\(b_{yx}\)) and which corresponds to the regression of \(x\) on \(y\) (\(b_{xy}\)).
Let's check the alternative assignment:
Calculate \(r^2\) for this alternative assignment: \(r^2 = b_{yx} \cdot b_{xy} = (-1) \cdot (-\frac{3}{2}) = \frac{3}{2}\). Since \(r^2\) cannot be greater than 1, this assignment is incorrect.
Therefore, the correct slopes are \(b_{yx} = -\frac{2}{3}\) and \(b_{xy} = -1\).
Using the correct slopes:
\(r^2 = b_{yx} \cdot b_{xy} = \left(-\frac{2}{3}\right) \times (-1) = \frac{2}{3}\)
The correlation coefficient \(r\) must have the same sign as the slopes \(b_{yx}\) and \(b_{xy}\). In this case, both \(b_{yx} = -\frac{2}{3}\) and \(b_{xy} = -1\) are negative.
Therefore, the correlation coefficient \(r\) must be negative.
\(r = -\sqrt{\frac{2}{3}}\)
The value of the correlation coefficient between \(x\) and \(y\) is \(-\sqrt{2/3}\).
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