It is given that ΔABC ∼ ΔYZX and Ar ΔABC : Ar ΔXYZ = 256 : 25. If AB = 12 cm, BC = 10 cm, CA = 15 cm, then what is the value of YZ (in cm)?
15/4
The correct answer is 15/4.
Similarly, the ratio of corresponding altitudes would be $\frac{16}{5}$. Understanding the correspondence between vertices is critical. If the similarity was stated as ΔABC ∼ ΔXYZ, then AB would correspond to XY, BC to YZ, and CA to XZ. Always pay close attention to the order of vertices in the similarity statement.
It is given that ΔABC ~ ΔXYZ and Area ΔABC : Area ΔXYZ = 81 : 25. If AB = 18 cm, BC = 10 cm, CA = 15 cm, then what is the side XZ (in cm)?
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Let ΔABC ~ ΔPQR and \(\frac{{ar\left( {{\rm{\Delta \;ABC}}} \right)}}{{ar\left( {{\rm{\Delta \;PQR}}} \right)}} = \frac{9}{{169}}\) . If AB = 12 cm, BC = 7 cm and AC = 8 cm, then PQ (in cm) is equal to:
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It is given that ΔABC ~ ΔXYZ and Area ΔABC : Area ΔXYZ = 81 : 25. If AB = 18 cm, BC = 10 cm, CA = 15 cm, then what is the side XZ (in cm)?
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