In a triangle, if the angles are in the ratio 1 ∶ 2 ∶ 3, then the ratio of the corresponding sides is:
1 ∶\(\sqrt 3 \)∶ 2
The correct answer is 1 ∶ \sqrt 3 ∶ 2.
So, 1 + \text{altitude}^2 = 4, which means \text{altitude}^2 = 3, and altitude = \sqrt{3}. This leg is opposite the 60^\circ angle. Thus, the sides opposite the angles 30^\circ, 60^\circ, and 90^\circ are in the ratio 1 : \sqrt{3} : 2. This confirms the result obtained using the Sine Rule for this specific triangle.
It is given that ΔABC ~ ΔXYZ and Area ΔABC : Area ΔXYZ = 81 : 25. If AB = 18 cm, BC = 10 cm, CA = 15 cm, then what is the side XZ (in cm)?
Given that Δ MAN and Δ CPT are congruent to each other such that ∠M = 75, ∠N = 65, ∠A = 40, ∠C = x/2, ∠P = 6y + 16. Find the value of (x – 5y).
If M is the mid-point of the side BC of ABC, and the area of ABM is 19 cm2 , then the area of ABC is:
It is given that ΔABC ∼ ΔYZX and Ar ΔABC : Ar ΔXYZ = 256 : 25. If AB = 12 cm, BC = 10 cm, CA = 15 cm, then what is the value of YZ (in cm)?
In trapezium ABCD, AB∥DC. The sides AD and BC are produced to meet at E. AB = 15 cm, CD = 10 cm, AD = 4 cm and BC = 5 cm, then DE = ?
In Δ ABC, ∠C = 70°. The bisectors of ∠A and<B meet BC and AC in points D and E, respectively. AD and BE intersect each other at P. What is the measure of ∠DPB?
If angles of triangle are in the ratio 3 : 4 : 5, then find the angles.
In ΔABC, ∠A = 48°. AB and AC is extended to points D and E respectively, if the bisectors of angle CBD and angle BCE meet at point O, then ∠BOC is equal to:
Let ΔABC ~ ΔPQR and \(\frac{{ar\left( {{\rm{\Delta \;ABC}}} \right)}}{{ar\left( {{\rm{\Delta \;PQR}}} \right)}} = \frac{9}{{169}}\) . If AB = 12 cm, BC = 7 cm and AC = 8 cm, then PQ (in cm) is equal to:
The side BC Δ ABC is produced to D. The bisectors of ∠ABC and ∠ACD meet at E. If AB = AC and ∠BEC = 24º, then the measure of ∠ABC is:
If sides of a triangle are 12 cm, 15 cm and 21 cm, then what is the inradius (in cm) of the triangle?
What is the area of quadrilateral ABCD?
It is given that ΔABC ~ ΔXYZ and Area ΔABC : Area ΔXYZ = 81 : 25. If AB = 18 cm, BC = 10 cm, CA = 15 cm, then what is the side XZ (in cm)?
Sides of two similar triangles are in the ratio 4 ∶ 9. Area of these triangles are in the ratio:
If the ratio of corresponding sides of 2 similar triangles is 2 ∶ 3. Then the ratio of their corresponding altitude is :