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Question

In an examination, B obtained 20% more marks than those obtained by A, and A obtained 10% less marks than those obtained by C. D obtained 20% more marks than those obtained by C. By what percentage are the marks obtained by D more than those obtained by A?

This question was previously asked in
SSC CGL 2020 Tier-II (English) Previous Year Paper (29-Jan-2022)
The correct answer is \(33\frac{1}{3} \)%

Understanding the Percentage Problem in Examination Marks

This problem involves calculating the percentage difference in marks obtained by different students based on given relationships. We are given how the marks of B, A, C, and D relate to each other in terms of percentages. Our goal is to find out by what percentage D's marks are more than A's marks.

Defining Variables for Student Marks

Let's represent the marks obtained by each student with a variable:

  • Let A be the marks obtained by student A.
  • Let B be the marks obtained by student B.
  • Let C be the marks obtained by student C.
  • Let D be the marks obtained by student D.

Translating Percentage Relationships into Equations

We are given the following information:

  1. B obtained 20% more marks than A.
    This can be written as: \( B = A + 20\% \text{ of } A = A + \frac{20}{100}A = A + 0.20A = 1.20A \)
  2. A obtained 10% less marks than C.
    This can be written as: \( A = C - 10\% \text{ of } C = C - \frac{10}{100}C = C - 0.10C = 0.90C \)
  3. D obtained 20% more marks than C.
    This can be written as: \( D = C + 20\% \text{ of } C = C + \frac{20}{100}C = C + 0.20C = 1.20C \)

We are asked to find the percentage by which D's marks are more than A's marks. This percentage difference is calculated using the formula:

\( \text{Percentage Difference} = \frac{\text{Marks of D} - \text{Marks of A}}{\text{Marks of A}} \times 100 \)
or \( \text{Percentage Difference} = \left(\frac{D - A}{A}\right) \times 100 \)
or \( \text{Percentage Difference} = \left(\frac{D}{A} - 1\right) \times 100 \)

Calculating the Ratio of D's Marks to A's Marks

To find the percentage difference, we need to express D and A in terms of a common reference, or find the ratio D/A. From the given equations, we have:

  • From equation 2: \( A = 0.90C \)
  • From equation 3: \( D = 1.20C \)

We can express C in terms of A from equation 2:

\( C = \frac{A}{0.90} \)

Now substitute this expression for C into the equation for D:

\( D = 1.20 \times \left(\frac{A}{0.90}\right) \)

Simplify the coefficient:

\( D = \frac{1.20}{0.90} \times A \)
\( D = \frac{120}{90} \times A \)
\( D = \frac{12}{9} \times A \)
\( D = \frac{4}{3} \times A \)

So, the ratio of D's marks to A's marks is \( \frac{D}{A} = \frac{4}{3} \).

Finding the Percentage Increase

Now we use the percentage difference formula:

\( \text{Percentage Difference} = \left(\frac{D}{A} - 1\right) \times 100 \)

Substitute \( \frac{D}{A} = \frac{4}{3} \):

\( \text{Percentage Difference} = \left(\frac{4}{3} - 1\right) \times 100 \)
\( \text{Percentage Difference} = \left(\frac{4}{3} - \frac{3}{3}\right) \times 100 \)
\( \text{Percentage Difference} = \left(\frac{4-3}{3}\right) \times 100 \)
\( \text{Percentage Difference} = \left(\frac{1}{3}\right) \times 100 \)
\( \text{Percentage Difference} = \frac{100}{3} \)
\( \text{Percentage Difference} = 33\frac{1}{3} \% \)

The marks obtained by D are \( 33\frac{1}{3}\% \) more than the marks obtained by A.

Summary of Calculations

Relationship Equation
B is 20% more than A \( B = 1.20A \)
A is 10% less than C \( A = 0.90C \)
D is 20% more than C \( D = 1.20C \)

Derived Relationship between D and A:

Step Calculation
From \( A = 0.90C \), find C in terms of A \( C = \frac{A}{0.90} \)
Substitute C in \( D = 1.20C \) \( D = 1.20 \times \frac{A}{0.90} \)
Simplify \( D = \frac{4}{3}A \)

Percentage increase of D over A:

Formula Calculation
\( \left(\frac{D-A}{A}\right) \times 100 \) \( \left(\frac{\frac{4}{3}A - A}{A}\right) \times 100 = \left(\frac{(\frac{4}{3}-1)A}{A}\right) \times 100 = \left(\frac{1}{3}\right) \times 100 = \frac{100}{3} = 33\frac{1}{3}\% \)

Conclusion on Percentage Difference

Based on the calculations, D obtained \( 33\frac{1}{3}\% \) more marks than A.

Revision Table: Key Percentage Concepts

Concept Explanation Formula Example
Percentage Increase Amount Y is P% more than Amount X. \( Y = X + \frac{P}{100}X = X\left(1 + \frac{P}{100}\right) \)
Percentage Decrease Amount Y is P% less than Amount X. \( Y = X - \frac{P}{100}X = X\left(1 - \frac{P}{100}\right) \)
Percentage Change The relative change from an old value (Old) to a new value (New). \( \frac{\text{New} - \text{Old}}{\text{Old}} \times 100\% \)

Additional Information: Working with Percentages

Working with percentages often involves converting them to decimals or fractions for calculations. A percentage represents a fraction out of 100. For example, 20% is equivalent to \( \frac{20}{100} = 0.20 \) or \( \frac{1}{5} \). 10% is \( \frac{10}{100} = 0.10 \) or \( \frac{1}{10} \).

When one quantity is a certain percentage more than another, you add that percentage of the base quantity to the base quantity. If it's a percentage less, you subtract. For example, if B has 20% more marks than A, and A has marks 'A', then the increase is \( 20\% \) of A, which is \( 0.20A \). So, B's marks are \( A + 0.20A = 1.20A \). If A has 10% less marks than C, and C has marks 'C', then the decrease is \( 10\% \) of C, which is \( 0.10C \). So, A's marks are \( C - 0.10C = 0.90C \).

The percentage difference between two quantities, say Q1 and Q2, relative to Q1 is \( \frac{Q2 - Q1}{Q1} \times 100\% \). If Q2 > Q1, this gives a positive percentage increase. If Q2 < Q1, it gives a negative percentage change (a decrease).

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Important Questions from Percentage

  1. In an examination, 25% of the candidates failed in Mathematics and 12% failed in English. If 10% of the candidates failed in both the subjects and 292 candidates passed in both the subjects, which one of the following is the number of total candidates appeared in the examination?

  2. What is the value of 9% of 5500 + 2.4% of 1100 - 40% of 1600?

  3. Population of a village is 7960 in which 4660 are female. If in that village 60% are literate in which 70% female are literate, then what is the number of literate male ?

  4. In an examination, Ram obtained 20 % more than Ashok but 10% less than Rajesh. If the marks obtained by Ashok is 1080. Then the Percentage marks obtained by Rajesh if the full marks is 2000 ;

  5. A student appeared in 6 papers. The maximum marks are the same for each paper. His marks in these papers are in the proportion of 5 : 6 : 7 : 8 : 9 : 10. Overall he scored 60%. In how many number of papers did he score less than 60% of the maximum marks?

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