Chamanlal, Arshad and Jagit Singh contested an election. All the votes polled were valid. Arshad got 35% of the total votes. For every 35 votes Chamanlal got 14 votes. The winner got 4950 more votes than the person who received the least number of votes. Find the total number of votes polled.
33000
This problem involves calculating the total number of votes polled in an election contested by three candidates: Chamanlal, Arshad, and Jagit Singh. We are given information about the percentage or share of votes received by some candidates and the difference in votes between the winner and the person who received the least votes. All polled votes are considered valid.
Let's find the share of votes for each candidate:
Let's simplify Chamanlal's fraction:
\[ \frac{14}{35} = \frac{2 \times 7}{5 \times 7} = \frac{2}{5} \]
To express this as a percentage, we multiply by 100%:
\[ \frac{2}{5} \times 100\% = \frac{200}{5}\% = 40\% \]
So, Chamanlal got 40% of the total votes. Chamanlal's votes are \(0.40T\).
Jagit Singh's percentage = \(100\% - 75\% = 25\%\).
Jagit Singh's votes are \(0.25T\).
Let's compare the percentages to find the winner and the person with the least votes:
Clearly, Chamanlal got the highest percentage (40%) and is the winner. Jagit Singh got the lowest percentage (25%) and received the least number of votes.
We are given that the winner got 4950 more votes than the person who received the least number of votes. This difference is between Chamanlal's votes and Jagit Singh's votes.
Difference in votes = Votes of Winner - Votes of Loser = 4950.
In terms of percentages, the difference is:
Difference in percentage = Percentage of Winner - Percentage of Loser = \(40\% - 25\% = 15\%\).
So, 15% of the total votes corresponds to 4950 votes.
We can write this as an equation:
\[ 15\% \text{ of } T = 4950 \]
\[ 0.15 \times T = 4950 \]
Now, we need to solve the equation for \(T\):
\[ T = \frac{4950}{0.15} \]
To make the division easier, we can multiply both the numerator and the denominator by 100 to remove the decimal:
\[ T = \frac{4950 \times 100}{0.15 \times 100} = \frac{495000}{15} \]
Now, let's perform the division:
\[ 495000 \div 15 = 33000 \]
So, the total number of votes polled is 33000.
Let's quickly verify our answer:
Sum of votes: \(13200 + 11550 + 8250 = 33000\). This matches the total.
Difference between winner (Chamanlal) and loser (Jagit Singh): \(13200 - 8250 = 4950\). This matches the given difference.
The calculated total number of votes, 33000, is consistent with all the conditions given in the problem.
| Candidate | Vote Share Information | Percentage of Total Votes | Votes (\(T=33000\)) |
|---|---|---|---|
| Arshad | 35% | 35% | 11550 |
| Chamanlal | 14 out of 35 votes | \(\frac{14}{35} = 40\%\) | 13200 |
| Jagit Singh | Remaining votes | \(100\% - (35\%+40\%) = 25\%\) | 8250 |
Percentage problems often involve translating word descriptions into mathematical equations. Key steps include:
In this election problem, the difference between the highest and lowest percentages was a direct translation of the given vote difference, allowing us to find the total number of votes.
The sum of two numbers is 680. If the bigger number is decreased by 15% and the smaller number is increased by 15%, then the resultant numbers are equal. Find the smaller number.
A number is decreased by 20% to get another number. The number so obtained is increased by 200% to get a third number. The difference of the third number and the original number is what percentage more or less than the difference of second and the third number?
In the first year the population of a town decreased by 5% due to the Corona virus first wave. In the next year it decreased again by 5% due to the second wave and in the third year it increased by 5%. At the end of the third year the population was 9,47,625. What was the population at the beginning of the first year?
Radha saves 25% of her income. If her expenditure increases by 20% and her income increases by 29%, then her savings increase by;
In an examination, 92% of the students passed and 480 students failed. If so, how many students appeared in the examination?
If the sum of 40% of a number and 30% of the same number is 70, then the number is:
By mistake, the reciprocal of a positive fraction got typed in place of itself, and thereby its value got reduced by \(\frac{175}{4}\%\) . What was the value of the fraction?
Rohit's income is Rs. 32000. If his expenses is 30 percent of total income, then what will be the saving of Rohit ?
In an examination, 45% of all the students who appeared are boys and the rest are girls. If 60% of the boys and 70% of the girls passed, then what is the percentage of students who failed?
In an examination, 25% of the candidates failed in Mathematics and 12% failed in English. If 10% of the candidates failed in both the subjects and 292 candidates passed in both the subjects, which one of the following is the number of total candidates appeared in the examination?
What is the value of 9% of 5500 + 2.4% of 1100 - 40% of 1600?
Population of a village is 7960 in which 4660 are female. If in that village 60% are literate in which 70% female are literate, then what is the number of literate male ?
In an examination, Ram obtained 20 % more than Ashok but 10% less than Rajesh. If the marks obtained by Ashok is 1080. Then the Percentage marks obtained by Rajesh if the full marks is 2000 ;
A student appeared in 6 papers. The maximum marks are the same for each paper. His marks in these papers are in the proportion of 5 : 6 : 7 : 8 : 9 : 10. Overall he scored 60%. In how many number of papers did he score less than 60% of the maximum marks?