In Δ ABC, the medians AD, BE and CF intersect at G (the centroid). If the area of Δ ABC is 72 cm², find the area of Δ AGB.
24 cm²
The three medians of a triangle intersect at the centroid G, which divides the triangle into six smaller triangles of equal area.
Triangles AGB, BGC, and CGA are each made up of two of these equal small triangles, so each has one-third of the total area.
\(\text{Area of } \triangle AGB = \frac{1}{3} \times 72 = 24\)
Hence, the area of triangle AGB is 24 cm².
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