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Question

In a regiment, the ratio between the number of officers to soldiers was 3 : 31 before the battle. In the battle, 6 officers and 22 soldiers were martyred, and the ratio became 1 : 13, the number of officers in the regiment before the battle was:

This question was previously asked in
SSC CGL 2016 (Tier 1) Previous Year Question Paper (11-Sep-2016) (Shift 2)
The correct answer is

21

Solving Regiment Ratio Problem: Officers and Soldiers

This problem involves a regiment where the ratio of officers to soldiers changes after some are lost in a battle. We need to find the initial number of officers.

Setting up the Ratio and Variables

Before the battle, the ratio of officers to soldiers was 3 : 31. We can represent the initial number of officers and soldiers using a common multiple, say \(x\).

  • Let the initial number of officers be \(3x\).
  • Let the initial number of soldiers be \(31x\).

Changes After the Battle

In the battle, 6 officers and 22 soldiers were martyred (lost). So, the number of officers and soldiers after the battle will be:

  • Number of officers after battle = Initial officers - Lost officers = \(3x - 6\).
  • Number of soldiers after battle = Initial soldiers - Lost soldiers = \(31x - 22\).

Forming the Equation from the New Ratio

After the battle, the ratio of officers to soldiers became 1 : 13. We can write this as an equation:

\[ \frac{\text{Number of officers after battle}}{\text{Number of soldiers after battle}} = \frac{1}{13} \]

Substitute the expressions for the number of officers and soldiers after the battle:

\[ \frac{3x - 6}{31x - 22} = \frac{1}{13} \]

Solving the Equation for x

To solve for \(x\), we can cross-multiply:

\[ 13 \times (3x - 6) = 1 \times (31x - 22) \]

Distribute the 13 on the left side:

\[ 39x - 78 = 31x - 22 \]

Now, we need to isolate the \(x\) terms on one side and the constant terms on the other side. Subtract \(31x\) from both sides:

\[ 39x - 31x - 78 = -22 \]

Simplify the \(x\) terms:

\[ 8x - 78 = -22 \]

Add 78 to both sides:

\[ 8x = -22 + 78 \]

\[ 8x = 56 \]

Divide by 8 to find the value of \(x\):

\[ x = \frac{56}{8} \]

\[ x = 7 \]

Calculating the Initial Number of Officers

The question asks for the number of officers in the regiment before the battle. We defined the initial number of officers as \(3x\). Now that we know \(x=7\), we can calculate the initial number of officers:

Initial officers = \(3x = 3 \times 7 = 21\).

Verification

Let's check if the numbers work with the ratios:

  • Initial officers = 21
  • Initial soldiers = \(31 \times 7 = 217\)
  • Initial ratio: 21 : 217. Dividing both by 7 gives 3 : 31. This matches the given initial ratio.
  • Officers after battle = \(21 - 6 = 15\)
  • Soldiers after battle = \(217 - 22 = 195\)
  • Ratio after battle: 15 : 195. Dividing both by 15 gives 1 : 13. This matches the given final ratio.

The calculation is correct.

The number of officers in the regiment before the battle was 21.

Revision Table: Regiment Ratio Problem

DetailBefore BattleAfter Battle
Ratio (Officers : Soldiers)3 : 311 : 13
Number of Officers\(3x\) (Let)\(3x - 6\)
Number of Soldiers\(31x\) (Let)\(31x - 22\)
Equation Setup\(\frac{3x - 6}{31x - 22} = \frac{1}{13}\)
Value of x\(x = 7\)
Actual Count (Officers)\(3 \times 7 = 21\)\(21 - 6 = 15\)
Actual Count (Soldiers)\(31 \times 7 = 217\)\(217 - 22 = 195\)

Additional Information: Understanding Ratios and Word Problems

A ratio is a comparison of two quantities. In this problem, the ratio helps us understand the proportional relationship between the number of officers and soldiers.

When solving word problems involving ratios and changes, it's often helpful to:

  • Represent the initial quantities using variables based on the given ratio (e.g., \(3x\) and \(31x\)).
  • Write expressions for the quantities after the changes occur (e.g., \(3x - 6\) and \(31x - 22\)).
  • Form an equation using the new ratio.
  • Solve the equation to find the value of the variable.
  • Use the value of the variable to find the actual quantities asked for in the question.
  • Always verify your answer by plugging the calculated numbers back into the problem statement to ensure all conditions are met.

Ratio problems often appear in various quantitative aptitude tests and real-life scenarios involving proportions.

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Important Questions from Simple Ratios

  1. Half of the villagers of a certain village have their own houses. One-fifth of the villagers cultivate paddy. One-third of the villagers are literate. Four-fifth of the villagers are under 25 years of age. Which one of the following statements is certainly correct ?

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  3. If P/Q = 8/9 and Q - P = 12, then what is the value of P?

  4. A child gets 1 random coin out of Re 1, Rs 2, and Rs 5 coins daily. He starts on 1st April and at the end of the month, he has coins in the ratio 5 ∶ 4 ∶ 6. Find the value of the coins with him

  5. Find the proportion equivalent to M : N : O : P if M : N = 8 : 15, N : O = 5 : 9 and O : P = 18 : 19 ?

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