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Question

₹1200 is divided among X, Y and Z such that 30 more than $3/5^{th}$ of X's share, ₹ 10 more than $2/5^{th}$ of Y's share and 20 more than $5/7^{th}$ of Z's share, all are equal. What is Z's share?

The correct answer is

₹299.698

Problem Analysis

We are given a total amount of ₹1200 to be divided among three individuals: X, Y, and Z. The condition is that specific expressions related to their shares are equal.

  • Let the shares of X, Y, and Z be represented by $X$, $Y$, and $Z$ respectively.
  • The total sum is $X + Y + Z = 1200$.
  • The problem states that:
    • $ \frac{3}{5}X + 30 $
    • $ \frac{2}{5}Y + 10 $
    • $ \frac{5}{7}Z + 20 $
    are all equal. Let this common value be $k$.

Setting Up Equations

We can express the individual shares ($X$, $Y$, $Z$) in terms of $k$:

  • From $ \frac{3}{5}X + 30 = k $: $ \frac{3}{5}X = k - 30 $ $ X = \frac{5}{3}(k - 30) $
  • From $ \frac{2}{5}Y + 10 = k $: $ \frac{2}{5}Y = k - 10 $ $ Y = \frac{5}{2}(k - 10) $
  • From $ \frac{5}{7}Z + 20 = k $: $ \frac{5}{7}Z = k - 20 $ $ Z = \frac{7}{5}(k - 20) $

Calculating the Common Value (k)

Substitute these expressions into the total sum equation $X + Y + Z = 1200$:

$ \frac{5}{3}(k - 30) + \frac{5}{2}(k - 10) + \frac{7}{5}(k - 20) = 1200 $

Expand the terms:

$ \frac{5}{3}k - 50 + \frac{5}{2}k - 25 + \frac{7}{5}k - 28 = 1200 $

Group the $k$ terms and the constant terms:

$ k \left( \frac{5}{3} + \frac{5}{2} + \frac{7}{5} \right) = 1200 + 50 + 25 + 28 $

Find a common denominator (30) for the fractions:

$ k \left( \frac{5 \times 10}{30} + \frac{5 \times 15}{30} + \frac{7 \times 6}{30} \right) = 1303 $

$ k \left( \frac{50 + 75 + 42}{30} \right) = 1303 $

$ k \left( \frac{167}{30} \right) = 1303 $

Solve for $k$:

$ k = 1303 \times \frac{30}{167} $

$ k = \frac{39090}{167} $

Calculating Z's Share

Now, use the value of $k$ to find Z's share using the formula $ Z = \frac{7}{5}(k - 20) $:

$ Z = \frac{7}{5} \left( \frac{39090}{167} - 20 \right) $

Convert 20 to a fraction with denominator 167:

$ Z = \frac{7}{5} \left( \frac{39090}{167} - \frac{20 \times 167}{167} \right) $

$ Z = \frac{7}{5} \left( \frac{39090 - 3340}{167} \right) $

$ Z = \frac{7}{5} \left( \frac{35750}{167} \right) $

Simplify the expression:

$ Z = \frac{7 \times 35750}{5 \times 167} $

$ Z = \frac{250250}{835} $

Divide both numerator and denominator by 5:

$ Z = \frac{50050}{167} $

Calculate the final value:

$ Z \approx 299.698199 $

Rounding to three decimal places, Z's share is ₹299.698.

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Important Questions from Simple Ratios

  1. A box containing the denominations of one rupee coins, five rupee coins and ten rupee coins amount to Rs.1360. There are equal number of coins in all denominations. What is the total number of coins in the box?
  2. The ratio of 20 hours to 7 days is equivalent to which of the following?
  3. The ratio between the prices of two bicycles is 15: 26. If the price of first is increased by 10% and that of second by 550, the ratio between the prices becomes 13: 22. What were the initial prices of the two bicycles?
  4. Ram and Sham together have ₹ 285. If $2/3^{rd}$ of money with Ram is equal to $3/5^{th}$ of money with Sham, then what is the money with Ram?
  5. The ratio between the prices of two bicycles is 15:26. If the price of first is increased by 10% and that of second by Rs. 550, the ratio between the prices is 13:22. What were the initial prices of the two bicycles?
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