₹299.698
We are given a total amount of ₹1200 to be divided among three individuals: X, Y, and Z. The condition is that specific expressions related to their shares are equal.
We can express the individual shares ($X$, $Y$, $Z$) in terms of $k$:
Substitute these expressions into the total sum equation $X + Y + Z = 1200$:
$ \frac{5}{3}(k - 30) + \frac{5}{2}(k - 10) + \frac{7}{5}(k - 20) = 1200 $
Expand the terms:
$ \frac{5}{3}k - 50 + \frac{5}{2}k - 25 + \frac{7}{5}k - 28 = 1200 $
Group the $k$ terms and the constant terms:
$ k \left( \frac{5}{3} + \frac{5}{2} + \frac{7}{5} \right) = 1200 + 50 + 25 + 28 $
Find a common denominator (30) for the fractions:
$ k \left( \frac{5 \times 10}{30} + \frac{5 \times 15}{30} + \frac{7 \times 6}{30} \right) = 1303 $
$ k \left( \frac{50 + 75 + 42}{30} \right) = 1303 $
$ k \left( \frac{167}{30} \right) = 1303 $
Solve for $k$:
$ k = 1303 \times \frac{30}{167} $
$ k = \frac{39090}{167} $
Now, use the value of $k$ to find Z's share using the formula $ Z = \frac{7}{5}(k - 20) $:
$ Z = \frac{7}{5} \left( \frac{39090}{167} - 20 \right) $
Convert 20 to a fraction with denominator 167:
$ Z = \frac{7}{5} \left( \frac{39090}{167} - \frac{20 \times 167}{167} \right) $
$ Z = \frac{7}{5} \left( \frac{39090 - 3340}{167} \right) $
$ Z = \frac{7}{5} \left( \frac{35750}{167} \right) $
Simplify the expression:
$ Z = \frac{7 \times 35750}{5 \times 167} $
$ Z = \frac{250250}{835} $
Divide both numerator and denominator by 5:
$ Z = \frac{50050}{167} $
Calculate the final value:
$ Z \approx 299.698199 $
Rounding to three decimal places, Z's share is ₹299.698.