In a bag the ratio of red balls to green balls is 4 ∶ 9. If 6 more green balls were added to the bag, the ratio of red balls to green balls would become 1 ∶ 3. How many red balls are there in the bag?
8
The problem describes a bag containing red and green balls, initially in a specific ratio. When the number of green balls changes, the ratio changes. We need to find the original number of red balls.
The initial ratio of red balls to green balls is given as 4 ∶ 9. This means that for every 4 red balls, there are 9 green balls. We can represent the number of balls using a variable. Let the common multiplier be \(x\).
The problem states that 6 more green balls were added to the bag. The number of red balls remains unchanged, but the number of green balls increases.
After adding the green balls, the ratio of red balls to green balls becomes 1 ∶ 3. We can set up an equation based on this new ratio:
$$ \frac{\text{Number of red balls}}{\text{Number of green balls}} = \frac{1}{3} $$
Substituting the expressions for the new number of balls:
$$ \frac{4x}{9x + 6} = \frac{1}{3} $$
To solve for \(x\), we can cross-multiply:
$$ 3 \times (4x) = 1 \times (9x + 6) $$
$$ 12x = 9x + 6 $$
Now, we isolate the term with \(x\) by subtracting \(9x\) from both sides:
$$ 12x - 9x = 6 $$
$$ 3x = 6 $$
Finally, divide by 3 to find the value of \(x\):
$$ x = \frac{6}{3} $$
$$ x = 2 $$
The question asks for the number of red balls in the bag. From our initial setup, the number of red balls is \(4x\). Now that we have found \(x = 2\), we can calculate the number of red balls:
Number of red balls = \(4 \times x = 4 \times 2 = 8\)
So, there are 8 red balls in the bag.
Let's check if this number of red balls (8) gives the correct ratios:
The numbers fit the conditions given in the problem, confirming our answer is correct.
| Step | Action | Explanation |
|---|---|---|
| 1 | Represent initial quantities | Use variables based on the initial ratio (4x, 9x). |
| 2 | Account for change | Update quantities after adding/removing items (4x, 9x + 6). |
| 3 | Set up equation | Use the new ratio to form an equation (\(\frac{4x}{9x+6} = \frac{1}{3}\)). |
| 4 | Solve for the variable | Algebraically solve the equation for \(x\). |
| 5 | Calculate required quantity | Substitute the value of \(x\) back into the expression for the quantity asked (4x). |
A ratio is a comparison of two quantities. It can be written in different ways, such as \(a:b\), \(\frac{a}{b}\), or "a to b". When solving problems involving changing ratios:
Ratio problems often involve setting up and solving linear equations or proportions, which is a fundamental skill in algebra and quantitative aptitude.
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