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Question

In a badminton knockout tournament with 57 players, what is the minimum number of matches needed to determine the winner?

This question was previously asked in
SSC Stenographer 2025 Question Paper (06-Aug-2025) Shift 2
The correct answer is
56

Understanding Knockout Tournaments

A knockout tournament, also known as a single-elimination tournament, is a competition format where the loser of each match is immediately eliminated from the tournament. The winner proceeds to the next round until only one competitor remains undefeated, who is declared the champion.

Calculating Minimum Matches

In any knockout tournament, regardless of the number of participants or rounds, there is a straightforward way to determine the minimum number of matches required. Each match results in the elimination of exactly one player.

To determine a single winner from a starting pool of competitors, all other competitors must be eliminated. If there are \(N\) players at the start of the tournament, there must be \(N - 1\) losers to end up with just one winner.

Since each match produces exactly one loser, the total number of matches needed is equal to the number of players who need to be eliminated.

Applying to the Badminton Tournament

In this specific badminton tournament:

  • Number of players (\(N\)): 57
  • Number of players to be eliminated: \(N - 1\)

Therefore, the calculation is:

Minimum number of matches = Number of players - 1

Minimum number of matches = \(57 - 1\)

Minimum number of matches = \(56\)

This means that a minimum of 56 matches must be played to determine the single winner from the 57 participants in the badminton knockout tournament.

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