If \(\sqrt{x}\) of \(\sqrt{2601}\) \(= (\sqrt{1089} + \sqrt{324}) \times 35\). Find the value of \(x\).
1225
Evaluate the known square roots first: \(\sqrt{2601} = 51\), \(\sqrt{1089} = 33\) and \(\sqrt{324} = 18\).
Substitute these values into the equation: \(\sqrt{x} \times 51 = (33 + 18) \times 35\).
Simplify the right side: \(33 + 18 = 51\), so \(\sqrt{x} \times 51 = 51 \times 35\).
Divide both sides by 51: \(\sqrt{x} = 35\).
Square both sides: \(x = 35^2 = 1225\).
Hence, the value of \(x\) is 1225.
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Important Questions from Surds and Indices
The value of \(\frac{{{{\left( {251} \right)}^3} + {{\left( {249} \right)}^3}}}{{25.1 \times 25.1 - 624.99 + 24.9 \times 24.9}}\) is 5 × 10 k , where the value of k is :
Find the value of m in \(\left(\frac{2}{7}\right)^{-3} \times \left(\frac{2}{7}\right)^{-5}=\left (\frac{2}{7}\right)^{-3m+1}\)
If √625 = 25; then√(.00000625/25)is:
A. 0.0025
B. 0.001
C. 0.0001
D. 0.0005Find the value of:
\(\sqrt{150}-\sqrt{54}-\sqrt{24}\)
If \(\sqrt{4624}=68\) , then the value of:
\(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)
