If \(\sqrt{x}\) of \(\sqrt{2601}\) \(= (\sqrt{1089} + \sqrt{324}) \times 35\). Find the value of \(x\).
1225
Evaluate the known square roots first: \(\sqrt{2601} = 51\), \(\sqrt{1089} = 33\) and \(\sqrt{324} = 18\).
Substitute these values into the equation: \(\sqrt{x} \times 51 = (33 + 18) \times 35\).
Simplify the right side: \(33 + 18 = 51\), so \(\sqrt{x} \times 51 = 51 \times 35\).
Divide both sides by 51: \(\sqrt{x} = 35\).
Square both sides: \(x = 35^2 = 1225\).
Hence, the value of \(x\) is 1225.
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Important Questions from Surds and Indices
The cube root of - 64 × - 1331 is:
If (27) m = (81) n, then m 2: mn = ?
if 49 n + 49 n + 49 n + 49 n + 49 n + 49 n + 49 n = 7 2221 , then n = ?
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The value of (0.3) [{(200 - 146)/(3 × 3 × 3)} - 3] is:
