(Give your answer to one decimal place.)
The question asks us to calculate the value of $\sqrt{180} + \sqrt{80}$, given the value of $\sqrt{45} + \sqrt{125}$. The final answer should be rounded to one decimal place.
First, simplify all the square root terms by factoring out perfect squares:
We are given that $\sqrt{45} + \sqrt{125} = 17.89$. Substitute the simplified terms:
$3\sqrt{5} + 5\sqrt{5} = 17.89$
Combine the terms: $8\sqrt{5} = 17.89$.
We need to find the value of $\sqrt{180} + \sqrt{80}$. Substitute the simplified terms:
$\sqrt{180} + \sqrt{80} = 6\sqrt{5} + 4\sqrt{5}$
Combine the terms: $10\sqrt{5}$.
We know $8\sqrt{5} = 17.89$. We need to find $10\sqrt{5}$.
We can find the value of $\sqrt{5}$ by dividing the given value by 8: $\sqrt{5} = \frac{17.89}{8}$.
Now substitute this into the expression we need to find:
$10\sqrt{5} = 10 \times \frac{17.89}{8}$
$10\sqrt{5} = \frac{10}{8} \times 17.89 = \frac{5}{4} \times 17.89$
$10\sqrt{5} = 1.25 \times 17.89 = 22.3625$
The question asks for the answer to one decimal place. Rounding $22.3625$ to one decimal place gives $22.4$.
If $\sqrt{2916} = 54$ then what is the value of the following?
$\sqrt{29.16} + \sqrt{0.2916} + \sqrt{0.002916} + \sqrt{0.00002916}$
If $\frac{2\sqrt{2}+\sqrt{7}}{2\sqrt{2}-\sqrt{7}} = x + y\sqrt{14}$, find the value of y.
Find the cube root of 78402752
Find the value of :
[(3 × 3 × 3 × 3 × 3 × 3) 6 ÷ (3 × 3 × 3 × 3) 7 × 3 4]
The cube root of - 64 × - 1331 is:
If (27) m = (81) n, then m 2: mn = ?
if 49 n + 49 n + 49 n + 49 n + 49 n + 49 n + 49 n = 7 2221 , then n = ?