All Exams Test series for 1 year @ ₹349 only
Question

If $\sqrt{45} + \sqrt{125} = 17.89$, then what will be the value of $\sqrt{180} + \sqrt{80}$?
(Give your answer to one decimal place.)

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper PDF (31-Jan-2021) (Shift 1)
The correct answer is
22.4

Simplifying Square Roots

The question asks us to calculate the value of $\sqrt{180} + \sqrt{80}$, given the value of $\sqrt{45} + \sqrt{125}$. The final answer should be rounded to one decimal place.

Key Term Simplification

First, simplify all the square root terms by factoring out perfect squares:

  • $\sqrt{45} = \sqrt{9 \times 5} = \sqrt{9} \times \sqrt{5} = 3\sqrt{5}$
  • $\sqrt{125} = \sqrt{25 \times 5} = \sqrt{25} \times \sqrt{5} = 5\sqrt{5}$
  • $\sqrt{180} = \sqrt{36 \times 5} = \sqrt{36} \times \sqrt{5} = 6\sqrt{5}$
  • $\sqrt{80} = \sqrt{16 \times 5} = \sqrt{16} \times \sqrt{5} = 4\sqrt{5}$

Using Given Equation

We are given that $\sqrt{45} + \sqrt{125} = 17.89$. Substitute the simplified terms:

$3\sqrt{5} + 5\sqrt{5} = 17.89$

Combine the terms: $8\sqrt{5} = 17.89$.

Calculating Target Value

We need to find the value of $\sqrt{180} + \sqrt{80}$. Substitute the simplified terms:

$\sqrt{180} + \sqrt{80} = 6\sqrt{5} + 4\sqrt{5}$

Combine the terms: $10\sqrt{5}$.

Finding the Final Value

We know $8\sqrt{5} = 17.89$. We need to find $10\sqrt{5}$.

We can find the value of $\sqrt{5}$ by dividing the given value by 8: $\sqrt{5} = \frac{17.89}{8}$.

Now substitute this into the expression we need to find:

$10\sqrt{5} = 10 \times \frac{17.89}{8}$

$10\sqrt{5} = \frac{10}{8} \times 17.89 = \frac{5}{4} \times 17.89$

$10\sqrt{5} = 1.25 \times 17.89 = 22.3625$

Rounding the Result

The question asks for the answer to one decimal place. Rounding $22.3625$ to one decimal place gives $22.4$.

Was this answer helpful?

Similar Questions

  1. What is the value of $\frac{4+\sqrt{2}}{\sqrt{2}+1}$?
  2. If $\sqrt{2916} = 54$ then what is the value of the following? 

    $\sqrt{29.16} + \sqrt{0.2916} + \sqrt{0.002916} + \sqrt{0.00002916}$

  3. $(\sqrt{5} + \sqrt{11})(\sqrt{5} - \sqrt{11})$ is equal to:
  4. What is the value of $\sqrt{75} + \sqrt{147}$?
  5. Find $\sqrt{\frac{1521}{1849}}$
  6. If $\frac{2\sqrt{2}+\sqrt{7}}{2\sqrt{2}-\sqrt{7}} = x + y\sqrt{14}$, find the value of y.

  7. If $x = 7 + 4\sqrt{3}$, then find the value of $\sqrt{x} + \frac{1}{\sqrt{x}}$
  8. If $\frac{3\sqrt{5} - 5}{3\sqrt{5} + 5} = a + b\sqrt{5}$, then find the value of b.
  9. Calculate the value of $\sqrt{80} + 4\sqrt{5}$ if $2\sqrt{5} + \sqrt{125} = 7x$
  10. What is the value of $\frac{\sqrt{5}+1}{\sqrt{5}-1}$ ?

Important Questions from Surds and Indices

  1. The cube root of - 64 × - 1331 is:

  2. If (27) m = (81) n, then m 2: mn = ?

  3. if 49 n +  49 n  +  49 n  +  49 n  +  49 n  +  49 n +  49 n  = 7 2221 , then n = ? 

  4. If a x= b y= c zand b 2= ac then y =

  5. The value of (0.3) [{(200 - 146)/(3 × 3 × 3)} - 3] is:

Need Expert Advice?
Upcoming Exams
RRB ALP
November 03, 2026
Test Series
RRB NTPC img
Railways
RRB NTPC Under Graduate 2026 New Mock Test Series
1612 Tests 1 Tests Free
1020 Attempts
4.3(516)
English, Hindi, Telugu +7 More
More Questions from RRB NTPC

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App