This solution finds the value of the expression $(x^2 - y^2)$ using the given definitions for $x$ and $y$. The process involves simplifying the terms, squaring them, and then finding their difference.
First, simplify the expression for $x$: $x = \frac{\sqrt{9}+1}{\sqrt{9}-1}$ Since $\sqrt{9} = 3$, we substitute this value: $x = \frac{3+1}{3-1} = \frac{4}{2}$ Thus, $x = 2$.
Next, simplify the expression for $y$: $y = \frac{\sqrt{16}+1}{\sqrt{16}-1}$ Since $\sqrt{16} = 4$, we substitute this value: $y = \frac{4+1}{4-1} = \frac{5}{3}$ Thus, $y = \frac{5}{3}$.
Now, calculate the squares of $x$ and $y$: $x^2 = 2^2 = 4$ $y^2 = (\frac{5}{3})^2 = \frac{25}{9}$
Finally, calculate the difference $(x^2 - y^2)$: $x^2 - y^2 = 4 - \frac{25}{9}$ To subtract, find a common denominator, which is 9: $x^2 - y^2 = \frac{4 \times 9}{9} - \frac{25}{9} = \frac{36}{9} - \frac{25}{9}$ $x^2 - y^2 = \frac{36 - 25}{9}$ $x^2 - y^2 = \frac{11}{9}$
Simplify: $3((\frac{5}{3})x^2 - 28x + 15) - 5(x^2 + 6x - 15)$
If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.
For the following equations, what are the values of a and b to have infinitely many solutions?
ax + by = 2
3x - (5 - 2ay) = 6
If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.
For the following equations, what are the values of a and b to have infinitely many solutions?
ax + by = 2
3x - (5 - 2ay) = 6
Simplify the following expression:
\(\frac{(x - y)^3 + (y - z)^3 + (z - x)^3}{(x - y)(y - z)(z - x)}\)