The problem asks for a number that, when added to itself 14 times, results in 135. Let the unknown number be represented by '$x$'.
Adding a number '$x$' to itself 14 times is equivalent to having 15 instances of the number added together:
$x + x + x + \dots + x \quad (15 \text{ times}) = 135$
This can be simplified using multiplication:
$15x = 135$
To find the value of '$x$', we need to divide 135 by 15:
$x = \frac{135}{15}$
Performing the division:
$x = 9$
The calculated number is 9. Comparing this result with the given options:
The number 9 matches Option A.
Simplify: $3((\frac{5}{3})x^2 - 28x + 15) - 5(x^2 + 6x - 15)$
If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.
For the following equations, what are the values of a and b to have infinitely many solutions?
ax + by = 2
3x - (5 - 2ay) = 6
If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.
For the following equations, what are the values of a and b to have infinitely many solutions?
ax + by = 2
3x - (5 - 2ay) = 6
Simplify the following expression:
\(\frac{(x - y)^3 + (y - z)^3 + (z - x)^3}{(x - y)(y - z)(z - x)}\)