The problem asks for a number that, when added to itself 14 times, results in 135. Let the unknown number be represented by '$x$'.
Adding a number '$x$' to itself 14 times is equivalent to having 15 instances of the number added together:
$x + x + x + \dots + x \quad (15 \text{ times}) = 135$
This can be simplified using multiplication:
$15x = 135$
To find the value of '$x$', we need to divide 135 by 15:
$x = \frac{135}{15}$
Performing the division:
$x = 9$
The calculated number is 9. Comparing this result with the given options:
The number 9 matches Option A.
Simplify: $3((\frac{5}{3})x^2 - 28x + 15) - 5(x^2 + 6x - 15)$
The numerator of a fraction is 5 less than its denominator. If 2 is subtracted from the numerator and 2 is added to the denominator, the fraction becomes $\frac{2}{5}$. Find the original fraction.
A group of 630 children is seated in rows for a group photo session. Each row contains three less children than the row in front of it. Which one of the following number of rows is not possible?
The letters L, M, N, 0, P, Q, R, S and T in their order are substituted by nine integers 1 to 9 but not in that order. 4 is assigned to P. The difference between P and T is 5. The difference between N and T is 3.
What is the integer assigned to N?
Four persons, Alok, Bhupesh, Chander and Dinesh have a total of Rs. 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact Rs. 5 more than Dinesh has.
Who has the maximum amount of money?
If x=3/2, then the value of 27x3-54x2+36x-11 is
If a+b+c = 6 and ab+bc+ca = 11, then the value of bc(b+c) + ca(c+a) +ab(a+b) +3abc is