Solving the Absolute Value Equation
The given equation is $|x \times 1| = 0$. This simplifies to $|x| = 0$.
Finding Solutions
The absolute value of a number, $|x|$, represents its distance from zero on the number line. The only number whose distance from zero is zero is zero itself. Therefore, the only solution to the equation $|x| = 0$ is $x = 0$.
Identifying Positive Solutions
The question specifically asks for the number of positive solutions. Positive numbers are strictly greater than zero ($x > 0$). Since the only solution found is $x = 0$, and 0 is not a positive number, there are no positive solutions to the equation.
Thus, the total count of positive solutions is 0.
Similar Questions
Simplify: $3((\frac{5}{3})x^2 - 28x + 15) - 5(x^2 + 6x - 15)$
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- Which of the following number, when added to itself 14 times gives 135 as result?
- The value of $p^2 - 7p + 12$ at $p = 3$ is:
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- Select the term that can replace the question mark (?) in the following equation.
$(2a^3 - 3)(5a^3 - 2) = 10 a^6 + ? + 6$ The numerator of a fraction is 5 less than its denominator. If 2 is subtracted from the numerator and 2 is added to the denominator, the fraction becomes $\frac{2}{5}$. Find the original fraction.
Important Questions from Algebric Equations
A group of 630 children is seated in rows for a group photo session. Each row contains three less children than the row in front of it. Which one of the following number of rows is not possible?
The letters L, M, N, 0, P, Q, R, S and T in their order are substituted by nine integers 1 to 9 but not in that order. 4 is assigned to P. The difference between P and T is 5. The difference between N and T is 3.
What is the integer assigned to N?
Four persons, Alok, Bhupesh, Chander and Dinesh have a total of Rs. 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact Rs. 5 more than Dinesh has.
Who has the maximum amount of money?
If x=3/2, then the value of 27x3-54x2+36x-11 is
If a+b+c = 6 and ab+bc+ca = 11, then the value of bc(b+c) + ca(c+a) +ab(a+b) +3abc is
