$(2a^3 - 3)(5a^3 - 2) = 10 a^6 + ? + 6$
The goal is to find the term represented by the question mark (?) in the equation \( (2a^3 - 3)(5a^3 - 2) = 10 a^6 + ? + 6 \). This requires expanding the product of the two binomials on the left side.
We multiply the two binomials using the distributive property (often remembered by the FOIL acronym: First, Outer, Inner, Last):
Expression: \( (2a^3 - 3)(5a^3 - 2) \)
Adding these results gives: \( 10a^6 - 4a^3 - 15a^3 + 6 \)
Combine the terms containing \( a^3 \):
\( -4a^3 - 15a^3 = (-4 - 15)a^3 = -19a^3 \)
The fully expanded form is: \( 10a^6 - 19a^3 + 6 \)
Comparing the expanded form \( 10a^6 - 19a^3 + 6 \) to the given equation \( 10 a^6 + ? + 6 \), we can see that the missing term is \( -19a^3 \).
Simplify: $3((\frac{5}{3})x^2 - 28x + 15) - 5(x^2 + 6x - 15)$
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What is the integer assigned to N?
Four persons, Alok, Bhupesh, Chander and Dinesh have a total of Rs. 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact Rs. 5 more than Dinesh has.
Who has the maximum amount of money?
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