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Question

If x = 25 and y = 13 then find:

$\sqrt{x^2 - 2xy + y^2}$

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
12

To find the value of \(\sqrt{x^2 - 2xy + y^2}\), we can recognize this expression as a form of the perfect square trinomial, \((a-b)^2\), which is equal to \(a^2 - 2ab + b^2\).

  1. Identify the expression: Given \(x^2 - 2xy + y^2\), it matches the pattern \((x-y)^2\).
  2. Rewrite the expression using the formula: You can write the given expression as \((x-y)^2\).
  3. Substitute the values of \(x\) and \(y\): Here, \(x = 25\) and \(y = 13\). Therefore, we have \((25 - 13)^2\).
  4. Calculate the value inside the square root: Simplify \(25 - 13\) to get \(12\).
  5. Apply the square root: The square root of \((12)^2\) is \(12\).

Thus, the value of \(\sqrt{x^2 - 2xy + y^2}\) is 12.

The correct answer is: 12.

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Important Questions from Algebric Equations

  1. If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.

  2. For the following equations, what are the values of a and b to have infinitely many solutions?

    ax + by = 2

    3x - (5 - 2ay) = 6

  3. If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.

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    ax + by = 2

    3x - (5 - 2ay) = 6

  5. Simplify the following expression: 
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