$\sqrt{x^2 - 2xy + y^2}$
To find the value of \(\sqrt{x^2 - 2xy + y^2}\), we can recognize this expression as a form of the perfect square trinomial, \((a-b)^2\), which is equal to \(a^2 - 2ab + b^2\).
Thus, the value of \(\sqrt{x^2 - 2xy + y^2}\) is 12.
The correct answer is: 12.
Simplify: $3((\frac{5}{3})x^2 - 28x + 15) - 5(x^2 + 6x - 15)$
If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.
For the following equations, what are the values of a and b to have infinitely many solutions?
ax + by = 2
3x - (5 - 2ay) = 6
If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.
For the following equations, what are the values of a and b to have infinitely many solutions?
ax + by = 2
3x - (5 - 2ay) = 6
Simplify the following expression:
\(\frac{(x - y)^3 + (y - z)^3 + (z - x)^3}{(x - y)(y - z)(z - x)}\)