The volume $V$ of a right circular cylinder is given by the formula:
$V = \pi r^2 h$
where $r$ is the radius and $h$ is the height.
Let the original radius be $r$ and the original height be $h$. The original volume, $V_1$, is:
$V_1 = \pi r^2 h$
The problem states that the height and radius are doubled. Therefore:
The new volume, $V_2$, is calculated using the new dimensions:
$V_2 = \pi (r')^2 h'$
Substituting the new values:
$V_2 = \pi (2r)^2 (2h) = \pi (4r^2)(2h) = 8 \pi r^2 h$
The increase in volume is the difference between the new volume and the original volume:
$\text{Increase} = V_2 - V_1 = 8 \pi r^2 h - \pi r^2 h = 7 \pi r^2 h$
The percentage increase is calculated as:
$\text{Percentage Increase} = \left( \frac{\text{Increase}}{\text{Original Volume}} \right) \times 100\%$
Plugging in the values:
$\text{Percentage Increase} = \left( \frac{7 \pi r^2 h}{V_1} \right) \times 100\% = \left( \frac{7 \pi r^2 h}{\pi r^2 h} \right) \times 100\%$
$\text{Percentage Increase} = 7 \times 100\% = 700\%$
Thus, the percentage increase in the cylinder's volume is 700%.
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)
The length and breadth of a cuboid are 50 cm and 75 cm, respectively. If the length of the diagonal is $17\sqrt{29}$ cm, then what is the volume (in $cm^{3}$) of the cuboid?