We need to find the ratio of the curved surface areas of two cones where their base diameters are equal, and their slant heights are in the ratio 3:4.
The formula for the curved surface area (CSA) of a cone is:
$CSA = \pi r l$
where $r$ is the radius of the base and $l$ is the slant height.
Let the radius of the base for both cones be $r$, since their diameters are equal.
Let the slant heights of the two cones be $l_1$ and $l_2$.
We are given the ratio: $\frac{l_1}{l_2} = \frac{3}{4}$
Calculate the curved surface area for the first cone ($CSA_1$):
$CSA_1 = \pi r l_1$
Calculate the curved surface area for the second cone ($CSA_2$):
$CSA_2 = \pi r l_2$
Find the ratio of their curved surface areas:
$\frac{CSA_1}{CSA_2} = \frac{\pi r l_1}{\pi r l_2}$
Cancel out the common terms ($\pi$ and $r$):
$\frac{CSA_1}{CSA_2} = \frac{l_1}{l_2}$
Substitute the given ratio of slant heights:
$\frac{CSA_1}{CSA_2} = \frac{3}{4}$
Therefore, the ratio of their curved surface areas is 3:4.
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)
The length and breadth of a cuboid are 50 cm and 75 cm, respectively. If the length of the diagonal is $17\sqrt{29}$ cm, then what is the volume (in $cm^{3}$) of the cuboid?