This solution explains how to calculate the total number of bricks required for constructing a wall of specified dimensions.
First, ensure all dimensions are in the same unit. We will use centimeters (cm).
Calculate the volume of a single brick ($V_{brick}$).
$V_{brick} = \text{Length} \times \text{Breadth} \times \text{Height}$
$V_{brick} = 25 \text{ cm} \times 5 \text{ cm} \times 20 \text{ cm} = 2500 \text{ cm}^3$
Calculate the volume of the wall ($V_{wall}$) using its dimensions.
$V_{wall} = \text{Length} \times \text{Breadth} \times \text{Height}$
$V_{wall} = 4000 \text{ cm} \times 80 \text{ cm} \times 600 \text{ cm} = 192,000,000 \text{ cm}^3$
Divide the total volume of the wall by the volume of one brick to find the number of bricks needed.
$Number \, of \, Bricks = \frac{V_{wall}}{V_{brick}}$
$Number \, of \, Bricks = \frac{192,000,000 \text{ cm}^3}{2500 \text{ cm}^3}$
$Number \, of \, Bricks = 76,800$
Result: 76,800 bricks are required.
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)
The length and breadth of a cuboid are 50 cm and 75 cm, respectively. If the length of the diagonal is $17\sqrt{29}$ cm, then what is the volume (in $cm^{3}$) of the cuboid?