Let the radii of the two spheres be $r_1$ and $r_2$.
The formula for the curved surface area of a sphere is $A = 4 \pi r^2$.
The ratio of the curved surface areas of the two spheres is given as $1 : 4$. Therefore:
$ \frac{A_1}{A_2} = \frac{4 \pi r_1^2}{4 \pi r_2^2} = \left(\frac{r_1}{r_2}\right)^2 $Given that $\frac{A_1}{A_2} = \frac{1}{4}$, we have:
$ \left(\frac{r_1}{r_2}\right)^2 = \frac{1}{4} $Taking the square root of both sides gives the ratio of the radii:
$ \frac{r_1}{r_2} = \sqrt{\frac{1}{4}} = \frac{1}{2} $So, the ratio of the radii $r_1 : r_2$ is $1 : 2$.
The formula for the volume of a sphere is $V = \frac{4}{3} \pi r^3$.
The ratio of the volumes of the two spheres is:
$ \frac{V_1}{V_2} = \frac{\frac{4}{3} \pi r_1^3}{\frac{4}{3} \pi r_2^3} = \left(\frac{r_1}{r_2}\right)^3 $Substituting the ratio of the radii ($ \frac{r_1}{r_2} = \frac{1}{2} $) calculated previously:
$ \frac{V_1}{V_2} = \left(\frac{1}{2}\right)^3 = \frac{1^3}{2^3} = \frac{1}{8} $Thus, the ratio of the volumes of the two spheres is $1 : 8$.
The ratio of the volumes is $1 : 8$, which corresponds to Option C.
Find the total surface area of a closed cylinder having a base radius of 70 m and a height of 110 m. [Use π = \(22\over7\)]
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)