Determine the ratio of the radius of a cylinder's base to the radius of a cone's base when both shapes have the same height and equal volumes.
The volume ($V$) formulas for a cylinder and a right circular cone are:
Where $r_{cylinder}$ and $r_{cone}$ are the radii of the bases, and $h$ is the common height.
Given that $V_{cylinder} = V_{cone}$ and the height $h$ is the same for both:
$ \pi r_{cylinder}^2 h = \frac{1}{3} \pi r_{cone}^2 h $
Cancel $\pi$ and $h$ from both sides (since $h \neq 0$):
$ r_{cylinder}^2 = \frac{1}{3} r_{cone}^2 $
Rearrange to find the ratio of the squared radii:
$ \frac{r_{cylinder}^2}{r_{cone}^2} = \frac{1}{3} $
Take the square root of both sides to find the ratio of the radii:
$ \frac{r_{cylinder}}{r_{cone}} = \sqrt{\frac{1}{3}} = \frac{1}{\sqrt{3}} $
To express this ratio $\frac{1}{\sqrt{3}}$ in the form $a:b$ commonly seen in options, we can simplify it. Rationalize the denominator by multiplying the numerator and denominator by $\sqrt{3}$:
$ \frac{1}{\sqrt{3}} = \frac{1 \times \sqrt{3}}{\sqrt{3} \times \sqrt{3}} = \frac{\sqrt{3}}{3} $
This corresponds to the ratio $\sqrt{3} : 3$. Therefore, the ratio of the radius of the base of the cylinder to that of the cone is $\sqrt{3} : 3$.
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)
The length and breadth of a cuboid are 50 cm and 75 cm, respectively. If the length of the diagonal is $17\sqrt{29}$ cm, then what is the volume (in $cm^{3}$) of the cuboid?