If PA = 3 cm and PB = 12 cm, find PT.
6 cm
By the tangent-secant power-of-a-point theorem, when a tangent PT and a secant PAB are drawn from the same external point P, \(PT^2 = PA \times PB\).
Substituting the given values, \(PT^2 = 3 \times 12 = 36\).
Taking the square root, \(PT = \sqrt{36} = 6\) cm.
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