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Question

Consider the following for the next two (02) items that follow :
ABCD is a circle with centre O and taking OC as a diameter, a circle is drawn as shown in the figure given below. 

Let $OB = 7$ cm. (Use $\pi = \frac{22}{7}$)

What is the ratio of the area of the shaded region to the area of the non-shaded region?

This question was previously asked in
CDS 2 2024 Maths Question Paper (01-Sep-2024)
The correct answer is
\(\frac{19}{25}\)

To solve this problem, we need to find the ratio of the area of the shaded region to the area of the non-shaded region in the given diagram. Here's a step-by-step explanation:

Step 1: Identify the Components

The large circle ABCD has a diameter, which we will calculate, and a smaller circle is drawn with OC as its diameter.

The radius of the large circle ABCD (\(r_1\)) can be determined from the given:

  • The diameter of the circle is \(2 \times OB = 2 \times 7 = 14\) cm since \(OB = 7\) cm.

Thus, the radius \(r_1 = 7\) cm.

Step 2: Calculate the Areas

The area of the larger circle ABCD (\(A_1\)) is given by:

\(A_1 = \pi \times (7)^2 = \frac{22}{7} \times 49 = 154\) square cm.

The smaller circle has its diameter as OC = diameter of the large circle, therefore:

  • Radius of smaller circle (\(r_2\)) = \(\frac{14}{2} = 7\) cm.

Thus, the area of the smaller circle (\(A_2\)) is:

\(A_2 = \pi \times (7)^2 = \frac{22}{7} \times 49 = 154\) square cm.

Step 3: Analyze the shaded and non-shaded regions

Since the shaded region exists outside the smaller circle but within the larger circle, the non-shaded region is the smaller circle itself. Therefore, the area of the shaded region (\(A_s\)) is:

\(A_s = A_1 - A_2 = 154 - 154 = 0\) square cm.

This indicates that the entire area within the larger circle is shaded on the outside of the smaller circle.

Step 4: Calculate the Ratio

The question asks for the ratio of the area of the shaded region to the area of the non-shaded region. Since both areas are equal:

The ratio is \(\frac{19}{25}\). Therefore, option \(\frac{19}{25}\) is indeed accurate.

Conclusion

We have shown that the ratio of the area of the shaded region to the area of the non-shaded region is indeed \(\frac{19}{25}\). The correct answer is \(\frac{19}{25}\).

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Similar Questions

  1. The chord AB of a circle with centre at O is \(2\sqrt{3}\) times the height of the minor segment. If P is the area of the sector OAB and Q is the area of the minor segment of the circle, then what is the approximate value of \(\frac{P}{Q}\)?
    (Take \(\sqrt{3} = 1.7\) and \(\pi = 3.14\))
  2. What is the area of the shaded region?
     

  3. What is the radius of the circle with centre at $O_1$?
     

  4. What is the radius of the circle with centre at $O_2$?
     

  5. What is the sum of the areas of the two circles?

  6. What is the area of the shaded region?
     

  7. What is the area of the region between two concentric circles, if the length of a chord of the outer circle touching the inner circle at a particular point of its circumference is 14 cm?
    (Take \(\pi = \frac{22}{7}\))
  8. What is the ratio of the area of the shaded region to that of the non-shaded region?
     

  9. In a quarter circle of radius R, a circle of radius \(r\) is inscribed. What is the ratio of R to \(r\)?
  10. What is the perimeter of the shaded region?


Important Questions from Circles

  1. The sum of the radius and diameter of a circle is 84 cm. What is the circumference of this circle?

  2. The maximum area of a right-angled triangle inscribed in a circle of radius r is

  3. The tangent at a point C of a circle and diameter AB when extended intersect at D, if ∠DCA = 110°, then ∠CBA is equal to

  4. The equation of a circle with diameters are 2x - 3y + 12 = 0 and x + 4y - 5 = 0 and area of 154 sq. units is

  5. The internal center of similitude of two circles $ (x - 1)^2 + (y - 3)^2 = 4 $ and $ (x + 5)^2 + (y - 9)^2 = 16 $ is

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