A circular field has a radius of 14 m. A uniform path of width 7 m is constructed all around the field on the outside. Find the area of the path. (Take π = 22/7)
770 sq m
The inner radius is \(r = 14\) m, and the outer radius including the path is \(R = 14 + 7 = 21\) m.
The area of the path is the difference of the two circles' areas: \(\pi(R^2 - r^2) = \frac{22}{7}(21^2 - 14^2)\).
This is \(\frac{22}{7}(441 - 196) = \frac{22}{7} \times 245\).
Calculating, \(\frac{22}{7} \times 245 = 22 \times 35 = 770\).
So the area of the path is \(770\) sq m.
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