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Question

If P = 96/ (95 × 97), Q = 97/ (96 × 98) and R = 1/97, then which of the following is TRUE?

This question was previously asked in
SSC CGL 2017 (Tier 1) Previous Year Paper (16-Aug-2017) (Shift 1)
The correct answer is

R < Q < P

Rewrite using \((n-1)(n+1)=n^2-1\): \(P=\tfrac{96}{96^2-1}\), \(Q=\tfrac{97}{97^2-1}\).

P vs Q: The function \(f(x)=\tfrac{x}{x^2-1}\) decreases for \(x>1\), so \(P>Q\).

Q vs R: \(Q=\tfrac{97}{97^2-1}>\tfrac{97}{97^2}=\tfrac{1}{97}=R\).

Therefore R < Q < P.

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