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Question

If \(\frac {8 + 2\sqrt 3}{3\sqrt 3 + 5} = a\sqrt 3 - b,\)  then the value of a + b is equal to:

This question was previously asked in
SSC CGL 2019 (Tier 2) GS Finance & Economics Previous Year Paper (17-Nov-2020)
The correct answer is

18

Understanding the Problem: Rationalizing Surds and Finding a + b

The problem asks us to find the value of \(a + b\) given an equation where a fraction with surds in the denominator is equal to an expression of the form \(a\sqrt 3 - b\). To solve this, we first need to simplify the given fraction by rationalizing the denominator. Rationalizing the denominator helps us to rewrite the expression in a simpler form that can be easily compared to \(a\sqrt 3 - b\).

Step-by-Step Solution: Rationalizing the Denominator

The given equation is:

\(\frac {8 + 2\sqrt 3}{3\sqrt 3 + 5} = a\sqrt 3 - b\)

We will start by rationalizing the left side of the equation. The denominator is \(3\sqrt 3 + 5\). The conjugate of \(3\sqrt 3 + 5\) is \(3\sqrt 3 - 5\). We multiply both the numerator and the denominator by this conjugate.

LHS \( = \frac {8 + 2\sqrt 3}{3\sqrt 3 + 5} \times \frac {3\sqrt 3 - 5}{3\sqrt 3 - 5}\)

Multiplying the Numerator

Numerator \( = (8 + 2\sqrt 3)(3\sqrt 3 - 5)\)

We use the distributive property (or FOIL method) to multiply the terms:

  • \(8 \times (3\sqrt 3) = 24\sqrt 3\)
  • \(8 \times (-5) = -40\)
  • \((2\sqrt 3) \times (3\sqrt 3) = 2 \times 3 \times \sqrt 3 \times \sqrt 3 = 6 \times 3 = 18\)
  • \((2\sqrt 3) \times (-5) = -10\sqrt 3\)

Adding these terms:

Numerator \( = 24\sqrt 3 - 40 + 18 - 10\sqrt 3\)

Combine like terms (terms with \(\sqrt 3\) and constant terms):

Numerator \( = (24\sqrt 3 - 10\sqrt 3) + (-40 + 18)\)

Numerator \( = 14\sqrt 3 - 22\)

Multiplying the Denominator

Denominator \( = (3\sqrt 3 + 5)(3\sqrt 3 - 5)\)

This is in the form \((x+y)(x-y) = x^2 - y^2\), where \(x = 3\sqrt 3\) and \(y = 5\).

Denominator \( = (3\sqrt 3)^2 - 5^2\)

Calculate \((3\sqrt 3)^2\):

\((3\sqrt 3)^2 = 3^2 \times (\sqrt 3)^2 = 9 \times 3 = 27\)

Calculate \(5^2\):

\(5^2 = 25\)

Denominator \( = 27 - 25 = 2\)

Simplifying the Fraction

Now we have the simplified numerator and denominator:

LHS \( = \frac{14\sqrt 3 - 22}{2}\)

We can divide each term in the numerator by the denominator:

LHS \( = \frac{14\sqrt 3}{2} - \frac{22}{2}\)

LHS \( = 7\sqrt 3 - 11\)

Comparing and Finding a and b

Now we compare the simplified left side with the right side of the original equation:

\(7\sqrt 3 - 11 = a\sqrt 3 - b\)

By comparing the coefficients of \(\sqrt 3\) and the constant terms on both sides, we can find the values of \(a\) and \(b\).

  • Coefficient of \(\sqrt 3\): \(a = 7\)
  • Constant term: \(-b = -11\), which means \(b = 11\)

Calculating a + b

The problem asks for the value of \(a + b\).

\(a + b = 7 + 11\)

\(a + b = 18\)

Thus, the value of \(a + b\) is 18.

Operation Calculation
Rationalize Denominator Multiply by \(\frac{3\sqrt 3 - 5}{3\sqrt 3 - 5}\)
Numerator Product \((8 + 2\sqrt 3)(3\sqrt 3 - 5) = 14\sqrt 3 - 22\)
Denominator Product \((3\sqrt 3 + 5)(3\sqrt 3 - 5) = 2\)
Simplified Expression \(\frac{14\sqrt 3 - 22}{2} = 7\sqrt 3 - 11\)
Compare with \(a\sqrt 3 - b\) \(a = 7\), \(b = 11\)
Calculate \(a+b\) \(7 + 11 = 18\)

Revision Table: Key Concepts

Concept Description
Rationalizing Denominator Eliminating surds (irrational numbers) from the denominator of a fraction, typically by multiplying by the conjugate.
Conjugate of \(x\sqrt a + y\sqrt b\) \(x\sqrt a - y\sqrt b\) (or \(x\sqrt a - y\) for \(x\sqrt a + y\)). The product of a binomial and its conjugate is always rational: \((x\sqrt a + y)(x\sqrt a - y) = (x\sqrt a)^2 - y^2\).
Comparing Expressions If \(c\sqrt d + e = f\sqrt d + g\), then \(c=f\) and \(e=g\), provided \(\sqrt d\) is an irrational surd and \(c, d, e, f, g\) are rational numbers.

Additional Information: Surds and Rational Numbers

Surds are irrational numbers that can be expressed as the root of a number, like \(\sqrt 2\), \(\sqrt 3\), \(\sqrt[3] 5\), etc. A number is a surd if its root cannot be simplified into a rational number. For example, \(\sqrt 4\) is not a surd because \(\sqrt 4 = 2\), which is a rational number.

A rational number is any number that can be expressed as a fraction \(\frac{p}{q}\) where \(p\) and \(q\) are integers and \(q \neq 0\). Examples include \(1\), \(-5\), \(1/2\), \(0.75\).

When we rationalize a denominator containing surds, we are essentially changing the form of the expression so that the denominator becomes a rational number, making it easier to work with or compare.

In this problem, after rationalizing, the expression \(7\sqrt 3 - 11\) is in the form \(a\sqrt 3 - b\), where \(a=7\) and \(b=11\). Both \(a\) and \(b\) are rational numbers (integers, specifically), which is typically expected in such problems unless otherwise stated.

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Important Questions from Rational or Irrational Numbers

  1. Which of the following number is irrational?

  2. Which of the following numbers will have an irrational square root?

  3. What is the square root of 16 + 6√7?

  4. A non-terminating but recurring decimal is:

  5. Which of the following is false?

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