Sum of four times a fraction and 7 times its reciprocal is 16. What is the fraction?
7/2
Let the fraction be \(x\). Then:
\[4x+\frac{7}{x}=16\]
Multiplying by \(x\) gives \(4x^2-16x+7=0\). Factorising:
\[(2x-1)(2x-7)=0\implies x=\tfrac{1}{2}\text{ or }\tfrac{7}{2}\]
From the given options, the fraction is \(\mathbf{\dfrac{7}{2}}\). Check: \(4(\tfrac{7}{2})+7(\tfrac{2}{7})=14+2=16\). ✓
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