Give the expression of \(8.\overline{48}\)
We are asked to express the repeating decimal \(8.\overline{48}\) as a fraction. A repeating decimal is a decimal in which one or more digits repeat infinitely.
To convert a repeating decimal into a fraction, we can follow these steps:
Let the given decimal be equal to a variable, say \(x\).
So, let \(x = 8.\overline{48}\)
This means \(x = 8.484848...\) (Equation 1)
Identify the number of repeating digits. In \(8.\overline{48}\), the repeating digits are '48', which is a block of 2 digits.
Multiply the equation by \(10^n\), where \(n\) is the number of repeating digits. Since there are 2 repeating digits, we multiply by \(10^2 = 100\).
\(100x = 100 \times 8.484848...\)
\(100x = 848.484848...\) (Equation 2)
Subtract Equation 1 from Equation 2. This step eliminates the repeating part of the decimal.
\(100x - x = 848.484848... - 8.484848...\)
\(99x = 840\)
Solve for \(x\) by dividing both sides by the coefficient of \(x\).
\(x = \frac{840}{99}\)
Simplify the fraction if possible. In this case, both 840 and 99 are divisible by 3 (since the sum of digits of 840 is 8+4+0=12, divisible by 3; the sum of digits of 99 is 9+9=18, divisible by 3).
\(x = \frac{840 \div 3}{99 \div 3} = \frac{280}{33}\)
The simplified fraction is \(\frac{280}{33}\). However, the options provided are not in simplified form. Let's check the options against the unsimplified fraction \(\frac{840}{99}\).
Comparing \(\frac{840}{99}\) with the given options:
Therefore, the expression of \(8.\overline{48}\) as a fraction among the given options is \(\frac{840}{99}\).
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