If f(x) = (x - 2)(x 2+ Px + 4) and (x - 3) is a factor of f(x), then what is the value of P?
-13/3
By the Factor Theorem, \((x-3)\) is a factor of \(f(x)\) iff \(f(3)=0\).
\[f(3)=(3-2)(9+3P+4)=13+3P=0\]
Solving: \(P=-\dfrac{13}{3}\).
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