Which number among 24963, 24973, 24983 and 24993 is divisible by 7?
24983
The question asks us to identify which number among 24963, 24973, 24983, and 24993 is divisible by 7. A number is divisible by 7 if, when divided by 7, the remainder is 0.
To find the answer, we need to perform division for each of the given options by 7 and check the remainder.
We divide 24963 by 7:
\( 24963 \div 7 \)
Performing the division:
\( 24963 = 7 \times 3566 + 1 \)
The remainder when 24963 is divided by 7 is 1. Since the remainder is not 0, 24963 is not divisible by 7.
We divide 24973 by 7:
\( 24973 \div 7 \)
Performing the division:
\( 24973 = 7 \times 3567 + 4 \)
The remainder when 24973 is divided by 7 is 4. Since the remainder is not 0, 24973 is not divisible by 7.
We divide 24983 by 7:
\( 24983 \div 7 \)
Performing the division:
\( 24983 = 7 \times 3569 + 0 \)
The remainder when 24983 is divided by 7 is 0. Since the remainder is 0, 24983 is divisible by 7.
We divide 24993 by 7:
\( 24993 \div 7 \)
Performing the division:
\( 24993 = 7 \times 3570 + 3 \)
The remainder when 24993 is divided by 7 is 3. Since the remainder is not 0, 24993 is not divisible by 7.
Based on the divisions performed, only the number 24983 results in a remainder of 0 when divided by 7. This means that 24983 is exactly divisible by 7.
| Number | Division by 7 Result | Remainder | Divisible by 7? |
|---|---|---|---|
| 24963 | \( 3566 \) | 1 | No |
| 24973 | \( 3567 \) | 4 | No |
| 24983 | \( 3569 \) | 0 | Yes |
| 24993 | \( 3570 \) | 3 | No |
Divisibility is a key concept in number theory. It tells us if one number can be divided by another number without leaving a remainder. We explored checking divisibility by 7 through direct division. While there isn't one simple, universally easy rule for divisibility by 7 for all numbers, direct calculation is always a reliable method.
For other numbers, simpler rules exist:
Understanding divisibility rules helps in simplifying calculations and solving problems related to factors and multiples.
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