Which of the following numbers Is divisible by 24?
49512
To determine if a number is divisible by 24, we need to check if it is divisible by both 3 and 8. This is because 24 is the product of two coprime numbers, 3 and 8 ($24 = 3 \times 8$). A number is divisible by 24 if and only if it satisfies the divisibility rules for both 3 and 8.
Let's apply these rules to each given option:
Since 52688 is not divisible by 3, it is not divisible by 24.
Since 49512 is divisible by both 3 and 8, it is divisible by 24.
Since 64760 is not divisible by 3, it is not divisible by 24.
Since 26968 is not divisible by 3, it is not divisible by 24.
| Number | Sum of Digits | Divisible by 3? | Last 3 Digits | Divisible by 8? | Divisible by 24? |
|---|---|---|---|---|---|
| 52688 | 29 | No | 688 | Yes | No |
| 49512 | 21 | Yes | 512 | Yes | Yes |
| 64760 | 23 | No | 760 | Yes | No |
| 26968 | 31 | No | 968 | Yes | No |
Based on the analysis, only the number 49512 is divisible by both 3 and 8, making it divisible by 24.
The number that is divisible by 24 among the given options is 49512.
| Divisor | Rule | Example (Number: 120) |
|---|---|---|
| 2 | Ends in 0, 2, 4, 6, or 8 | 120 ends in 0. Yes. |
| 3 | Sum of digits is divisible by 3 | $1+2+0 = 3$. 3 is divisible by 3. Yes. |
| 4 | Last two digits form a number divisible by 4 | Last two digits form 20. 20 is divisible by 4. Yes. |
| 5 | Ends in 0 or 5 | 120 ends in 0. Yes. |
| 6 | Divisible by both 2 and 3 | 120 is divisible by 2 and 3. Yes. |
| 8 | Last three digits form a number divisible by 8 | Last three digits form 120. $120 \div 8 = 15$. Yes. |
| 9 | Sum of digits is divisible by 9 | $1+2+0 = 3$. 3 is not divisible by 9. No. |
| 10 | Ends in 0 | 120 ends in 0. Yes. |
| 12 | Divisible by both 3 and 4 | 120 is divisible by 3 and 4. Yes. |
To check divisibility by a composite number (a number with factors other than 1 and itself), you can often break it down into its coprime factors. If a number is divisible by all its coprime factors, it is divisible by the composite number. For example:
This method works because the factors used are coprime (their greatest common divisor is 1). For example, you cannot check divisibility by 4 by checking divisibility by 2 and 2, because 2 and 2 are not coprime.
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