If an angle is 3 times its complement, what is the angle?
67.5°
Let the angle be \(x\). Its complement is \(90^\circ - x\).
Given: \(x = 3(90^\circ - x)\)
\(x = 270^\circ - 3x \Rightarrow 4x = 270^\circ \Rightarrow x = 67.5^\circ\)
Check: complement \(= 22.5^\circ\) and \(3 \times 22.5^\circ = 67.5^\circ\).
Hence, the angle is 67.5°.
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Two parallel lines are intersected by a transversal, the corresponding angles are:
There are three points P, Q and R on a straight line such that PQ : QR = 3 : 5. If n is the number of possible values of PQ : PR, then what is n equal to ?
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Express 65° in radian :
The measure of an angle for which the measure of the supplement is four times the measure of the complement is:
