If △ABC~△DEF, and ∠A=50°, ∠B=60°, then ∠E=:
60°
Since triangle ABC is similar to triangle DEF, corresponding angles are equal: \(\angle A = \angle D\), \(\angle B = \angle E\), and \(\angle C = \angle F\).
Given \(\angle A = 50°\) and \(\angle B = 60°\), since the correspondence gives \(\angle E = \angle B\).
So \(\angle E = 60°\).
Hence, the answer is 60°.
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Important Questions from Triangles, Congruence and Similarity
Angle between the internal bisectors of two angles ∠B and ∠C of a ΔABC is 132°, then the value of ∠A is
In ΔPQR, PQ = PR and S is a point on QR such that ∠PSQ = 96° + ∠QPS and ∠QPR = 132°. What is the measure of ∠PSR?
In Δ ABC, ∠A = 50°. If the bisectors of the angle B and angle C, meet at a point O, then ∠BOC is equal to:
Triangle ABC is right angled at B. BD is an altitude intersecting AC at D. If AC = 9 cm and CD = 3 cm. then find the measure of AB (in cm).
The base and altitude of an isosceles triangle are 10 cm and 12 cm respectively. Then the length of each equal side is:
