Angle between the internal bisectors of two angles ∠B and ∠C of a ΔABC is 132°, then the value of ∠A is
84°
Let's analyze the given problem involving a triangle and its internal angle bisectors. We are given a triangle ΔABC, and the internal bisectors of angles ∠B and ∠C meet at a point, say I. The angle formed at this point I, which is ∠BIC, is given as 132°. We need to find the measure of angle ∠A.
An internal angle bisector of a triangle divides the angle into two equal parts. The point where the internal angle bisectors of a triangle meet is called the incenter. This point is equidistant from the sides of the triangle.
There is a standard formula that relates the angle formed by the internal bisectors of two angles of a triangle to the third angle of the triangle. If the internal bisectors of ∠B and ∠C of ΔABC meet at I, the angle ∠BIC is given by the formula:
\[ \angle \text{BIC} = 90^\circ + \frac{\angle \text{A}}{2} \]
We are given that the angle between the internal bisectors of ∠B and ∠C is 132°. So, we have:
\[ \angle \text{BIC} = 132^\circ \]
Now, we can substitute this value into the formula:
\[ 132^\circ = 90^\circ + \frac{\angle \text{A}}{2} \]
To find the value of ∠A, we need to isolate it. First, subtract 90° from both sides of the equation:
\[ 132^\circ - 90^\circ = \frac{\angle \text{A}}{2} \]
\[ 42^\circ = \frac{\angle \text{A}}{2} \]
Now, multiply both sides by 2 to solve for ∠A:
\[ \angle \text{A} = 42^\circ \times 2 \]
\[ \angle \text{A} = 84^\circ \]
Thus, the value of angle ∠A is 84°.
If ∠A = 84°, let's calculate ∠BIC using the formula:
\[ \angle \text{BIC} = 90^\circ + \frac{84^\circ}{2} \]
\[ \angle \text{BIC} = 90^\circ + 42^\circ \]
\[ \angle \text{BIC} = 132^\circ \]
This matches the given information, confirming our calculation is correct.
| Concept | Description | Formula |
|---|---|---|
| Sum of angles in a triangle | The sum of the interior angles of any triangle is 180°. | ∠A + ∠B + ∠C = 180° |
| Angle between internal bisectors (∠B and ∠C) | Angle formed by the intersection of internal bisectors of two angles. | ∠BIC = 90° + ∠A/2 |
| Angle between external bisectors (∠B and ∠C) | Angle formed by the intersection of external bisectors of two angles. | Angle = 90° - ∠A/2 |
| Angle between internal bisector (∠B) and external bisector (∠C) | Angle formed by the intersection of internal bisector of one angle and external bisector of another. | Angle = ∠A/2 |
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