The base and altitude of an isosceles triangle are 10 cm and 12 cm respectively. Then the length of each equal side is:
13 cm
We are given an isosceles triangle with a base of 10 cm and an altitude of 12 cm. An isosceles triangle is defined as a triangle that has two sides of equal length. The altitude to the base of an isosceles triangle is a perpendicular line segment from the vertex opposite the base to the base. This altitude has important properties that help us solve this problem.
In an isosceles triangle, the altitude drawn to the base does more than just provide the height; it also bisects the base. This means it divides the base into two segments of equal length. Furthermore, this altitude splits the isosceles triangle into two congruent right-angled triangles.
Let's consider our specific triangle:
When the altitude is drawn to the base, it creates two right-angled triangles. Each of these right-angled triangles has:
The length of half the base is $\frac{10 \text{ cm}}{2} = 5 \text{ cm}$.
So, for each right-angled triangle, we have:
To find the length of the hypotenuse in a right-angled triangle, we use the Pythagorean theorem. This theorem states that the square of the length of the hypotenuse ($c$) is equal to the sum of the squares of the lengths of the other two sides ($a$ and $b$). The formula is: $a^2 + b^2 = c^2$.
In our case, the legs are 5 cm and 12 cm, and the hypotenuse is the equal side we want to find. Let $s$ represent the length of the equal side.
Using the Pythagorean theorem:
$\text{Leg 1}^2 + \text{Leg 2}^2 = \text{Hypotenuse}^2$
$(5 \text{ cm})^2 + (12 \text{ cm})^2 = s^2$
$25 \text{ cm}^2 + 144 \text{ cm}^2 = s^2$
$169 \text{ cm}^2 = s^2$
To find $s$, we take the square root of both sides:
$s = \sqrt{169 \text{ cm}^2}$
$s = 13 \text{ cm}$
So, the length of each equal side of the isosceles triangle is 13 cm.
By using the property of the altitude in an isosceles triangle and applying the Pythagorean theorem to the resulting right-angled triangles, we calculated the length of the equal side. The calculation shows that the length is 13 cm.
| Item | Value/Formula | Result |
|---|---|---|
| Base | 10 cm | - |
| Altitude | 12 cm | - |
| Half Base | Base / 2 | 5 cm |
| Pythagorean Theorem | Leg1$^2$ + Leg2$^2$ = Hypotenuse$^2$ | - |
| Calculation | $5^2 + 12^2 = s^2$ <br> $25 + 144 = s^2$ <br> $169 = s^2$ | - |
| Equal Side (s) | $\sqrt{169}$ | 13 cm |
| Concept | Relevance to Isosceles Triangle Altitude |
|---|---|
| Isosceles Triangle Properties | Two equal sides, two equal base angles. Altitude to base is median and angle bisector. |
| Right-Angled Triangle | Altitude creates two right triangles. Allows use of Pythagorean theorem. |
| Pythagorean Theorem ($a^2 + b^2 = c^2$) | Used to find the length of the equal side (hypotenuse) using the altitude (one leg) and half the base (other leg). |
Triangle geometry involves many shapes and formulas. Here are some related concepts that are often encountered:
Understanding these concepts helps in tackling a wider range of geometry problems.
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