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Question

In an urban project, triangular plots with side ratios 3:4:5 are allocated. If the perimeter is 60 m, find the area.

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
150 m²

Triangular Plot Area Calculation

The problem asks us to find the area of a triangular plot given its side ratios and perimeter.

Understanding Side Ratios and Perimeter

  • The side ratios are given as 3:4:5. This is a key indicator of a right-angled triangle, as it forms a Pythagorean triple ($3^2 + 4^2 = 5^2$).
  • The perimeter of the plot is 60 m. The perimeter is the sum of the lengths of all sides.

Calculating Actual Side Lengths

Let the sides of the triangle be $3x$, $4x$, and $5x$, where $x$ is a common multiplier.

The perimeter is the sum of these sides:

$ \text{Perimeter} = 3x + 4x + 5x $

$ \text{Perimeter} = 12x $

We are given that the perimeter is 60 m:

$ 12x = 60 \text{ m} $

Solve for $x$:

$ x = \frac{60}{12} $

$ x = 5 \text{ m} $

Now, calculate the actual lengths of the sides:

  • Side 1: $3x = 3 \times 5 = 15$ m
  • Side 2: $4x = 4 \times 5 = 20$ m
  • Side 3: $5x = 5 \times 5 = 25$ m

Determining Triangle Type and Area

Since the sides are in the ratio 3:4:5, the triangle is a right-angled triangle. The sides 15 m and 20 m are the base and height (the two shorter sides perpendicular to each other).

The formula for the area of a right-angled triangle is:

$ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} $

Substitute the values of the base and height:

$ \text{Area} = \frac{1}{2} \times 15 \text{ m} \times 20 \text{ m} $

$ \text{Area} = \frac{1}{2} \times 300 \text{ m}^2 $

$ \text{Area} = 150 \text{ m}^2 $

Final Answer

The area of the triangular plot is 150 m².

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  2. A right-angled triangle ABC has legs AB=6 cm and BC=8 cm. An altitude BD is drawn from the vertex B to the hypotenuse AC. What is the length of the altitude BD?
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Important Questions from Triangles, Congruence and Similarity

  1. Angle between the internal bisectors of two angles ∠B and ∠C of a ΔABC is 132°, then the value of ∠A is

  2. In ΔPQR, PQ = PR and S is a point on QR such that ∠PSQ = 96° + ∠QPS and ∠QPR = 132°. What is the measure of ∠PSR?

  3. In Δ ABC, ∠A = 50°. If the bisectors of the angle B and angle C, meet at a point O, then ∠BOC is equal to:

  4. Triangle ABC is right angled at B. BD is an altitude intersecting AC at D. If AC = 9 cm and CD = 3 cm. then find the measure of AB (in cm).

  5. The base and altitude of an isosceles triangle are 10 cm and 12 cm respectively. Then the length of each equal side is:

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