We are comparing two triangles, $\Delta PQR$ and $\Delta STU$.
The given information is:
The Side-Angle-Side (SAS) congruence rule states that if two sides and the angle included between them in one triangle are equal to the corresponding two sides and the included angle in another triangle, then the triangles are congruent.
In this problem:
Therefore, based on the SAS congruence rule, $\Delta PQR$ is congruent to $\Delta STU$.
Angle between the internal bisectors of two angles ∠B and ∠C of a ΔABC is 132°, then the value of ∠A is
In ΔPQR, PQ = PR and S is a point on QR such that ∠PSQ = 96° + ∠QPS and ∠QPR = 132°. What is the measure of ∠PSR?
In Δ ABC, ∠A = 50°. If the bisectors of the angle B and angle C, meet at a point O, then ∠BOC is equal to:
Triangle ABC is right angled at B. BD is an altitude intersecting AC at D. If AC = 9 cm and CD = 3 cm. then find the measure of AB (in cm).
The base and altitude of an isosceles triangle are 10 cm and 12 cm respectively. Then the length of each equal side is: