We are comparing two triangles, $\Delta PQR$ and $\Delta STU$.
The given information is:
The Side-Angle-Side (SAS) congruence rule states that if two sides and the angle included between them in one triangle are equal to the corresponding two sides and the included angle in another triangle, then the triangles are congruent.
In this problem:
Therefore, based on the SAS congruence rule, $\Delta PQR$ is congruent to $\Delta STU$.
The radius of the circumcircle of an equilateral triangle of √3 unit side, is:
If the ratio of the angles of a triangle is 3 : 5 : 7, find the value of the largest angle.
A. 36°
B. 60°
C. 84°
D. 15°
If ΔABC and Δ PQR are similar and \(\rm\frac{BC}{QR} = \frac{1}{3}\) , find \(\rm\frac{ar(\Delta PQR)} {ar(\Delta BCA)}\)
If the angles of a triangle are in the ratio of 2 : 5 : 8, then find the value of the smallest angle.
ABCD is a parallelogram. Side BC is produced to E such that BC = CE. Join AE which intersects side CD at P. The area of triangle ABE is: