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Question

If a product of 0.225, 0.36 and a number N is 243, then what is the value of number N?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
3000

The problem asks us to find the value of a number denoted as N, given that the product of 0.225, 0.36, and N equals 243.

Setting up the Equation

We can represent the given information as a mathematical equation:

$0.225 \times 0.36 \times N = 243$

Calculating the Product of Decimals

First, let's find the product of the two given decimal numbers, 0.225 and 0.36.

$0.225 \times 0.36 = 0.081$

To verify:

$ \frac{225}{1000} \times \frac{36}{100} = \frac{225 \times 36}{1000 \times 100} = \frac{8100}{100000} = 0.081 $

Solving for Number N

Now, substitute this product back into the equation:

$0.081 \times N = 243$

To find the value of N, we need to divide 243 by 0.081:

$N = \frac{243}{0.081}$

To simplify the division, we can multiply the numerator and denominator by 1000 to remove the decimal:

$N = \frac{243 \times 1000}{0.081 \times 1000} = \frac{243000}{81}$

Now, perform the division:

$N = 3000$

Conclusion

The value of the number N is 3000.

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Important Questions from Decimals

  1. The value of \(\frac{1}{4} + \frac{{[{{(20.35)}^2} - {{(8.35)}^2}] \times 0.0175}}{{{{(1.05)}^2} + (1.05)(27.65)}}\)  is:

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