The problem asks us to find the value of a number denoted as N, given that the product of 0.225, 0.36, and N equals 243.
We can represent the given information as a mathematical equation:
$0.225 \times 0.36 \times N = 243$
First, let's find the product of the two given decimal numbers, 0.225 and 0.36.
$0.225 \times 0.36 = 0.081$
To verify:
$ \frac{225}{1000} \times \frac{36}{100} = \frac{225 \times 36}{1000 \times 100} = \frac{8100}{100000} = 0.081 $
Now, substitute this product back into the equation:
$0.081 \times N = 243$
To find the value of N, we need to divide 243 by 0.081:
$N = \frac{243}{0.081}$
To simplify the division, we can multiply the numerator and denominator by 1000 to remove the decimal:
$N = \frac{243 \times 1000}{0.081 \times 1000} = \frac{243000}{81}$
Now, perform the division:
$N = 3000$
The value of the number N is 3000.
Simplify the given expression.
$9 \times 0.9 \times 0.09 \times 0.009 \times \frac{1}{0.3} \times \frac{1}{0.03} \times \frac{1}{0.003}$
Arrange the following numbers in their increasing order.
(1) $-0.96$
(2) $0.83$
(3) $0.24$
(4) $-0.64$
(5) $0.58$
The value of \(\frac{1}{4} + \frac{{[{{(20.35)}^2} - {{(8.35)}^2}] \times 0.0175}}{{{{(1.05)}^2} + (1.05)(27.65)}}\) is:
The value of \(0.4\overline 6 + 0.7\overline {23} - 0.3\overline 9 \times 0.\overline 7 \) is:
The value of \(\frac{48.3\times[(4.95)^2+4.95\times13.25]}{[(12.55)^2-(5.65)^2]\times19.8} \) is:
Find the value of (1.6) 3 - (0.9) 3 - (0.7) 3.
What is the value of x, if \(5\left( {1 - \frac{x}{5}} \right) - (5 - x) - \frac{1}{{200}}{\rm{of (20 - x) = 0}}{\rm{.08}}\) ?